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non-quake (physics)

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  • 09-11-1999 8:02pm
    #1
    Vincent
    Registered Users Posts: 625 ✭✭✭


    A ball is thrown vertically upwards from ground level with an initial speed of 20m/s

    what is the hightest height reached?

    Can someone please explain how to do this, i dont want the answer on it's own,

    (i wasn't in when we were doin this)


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    #2
    El_Presidente
    Closed Accounts Posts: 1,484 ✭✭✭El_Presidente


    k , its like this...
    u = initial velocity
    v = final velocity
    a = aceleration
    S = Distance

    v(squared) = u(squared) + 2AS


    u = 20
    v = 0
    a = -9.8
    t dosent matter
    S is what your looking for.

    0*0 = 20*20 + 2(-9. sunglasses.gif(S)
    -400 = -19.6(S)

    S= 20.0408 meters


    I think ( but its been a while since i'v done one of those)


    El


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    #3
    El_Presidente
    Closed Accounts Posts: 1,484 ✭✭✭El_Presidente


    er, ok, where the smily thing is there should be an eight, so thats -9.8


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    #4
    Vincent
    Registered Users Posts: 625 ✭✭✭Vincent


    thanks El_Presidente, much obliged smile.gif


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