C++ char FAR question

ikoonman

I understand (by reading on web) what this is and that it's not quite standard practice to use it these days. But in a project I am doing I need to use it as it's defined in a Windows API structure.

My question is: (I am a bit new to this) I am having trouble referencing the content of the buffer. (The structure is LPWSABUF).

Would i not simply be able to show the buffer with something like:

LPWSABUF tmpbuf;

...
...

printf("Buffer=%s\n", (char *) *tmpbuf.buf);

Any help would be greatly appreciated.
TIA

RazorEdge

typedef struct __WSABUF {
  u_long [URL="http://www.boards.ie/vbulletin/"]len[/URL];
  char FAR* [URL="http://www.boards.ie/vbulletin/"]buf[/URL];
} WSABUF, 
*LPWSABUF;

You can ignore the FAR attribute as it has no meaning on Win32.

LPWSABUF is not a buffer. It is a pointer to a structure of type WSABUF which has a member called buf. Therefore to reference buf, you must access it like this.

printf("Buffer=%s\n",tmpbuf->buf);

printf assumes that buf points to a NULL terminated string.

As tmpbuf is a pointer, be sure that it points to allocated WSABUF structure. This structures buf pointer should point to good memory that conatins a NULL terminated string also.

ikoonman

Ok, but the variable i am working with is declared as a LPWSABUF (as opposed to WSABUF), which is a pointer to said structure.

Is your printf statement still valid then?