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Maths Paper 1

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  • Closed Accounts Posts: 160 ✭✭helles belles


    holy crap!!!
    The paper is up already!!!!!!!


  • Closed Accounts Posts: 636 ✭✭✭NADA


    I did the honours paper. I thought it was very tough at the beginning. I could not get q3 part (A) Q1 part (A) for ages. Got everything else worked out. Then came back at about 11:50 and got them both worked out. I knew how to do all the paper. Just hope I didn make many blunders. Definately looking at an A1.


  • Closed Accounts Posts: 902 ✭✭✭d4gurl


    I cant believe people thot hons maths was easy! I couldnt do any of it!im so depressed! :( I swear it went awful! What did people get for the last part of 8? I really hated that paper!!!


  • Closed Accounts Posts: 4,564 ✭✭✭Naikon


    Eamoss you are right you factorise the equation and solve it.
    Or you could use the quadratic formula as an alternitive;)
    (Easier option in my opinion)


  • Registered Users Posts: 612 ✭✭✭JoseJones


    Raphael wrote:
    I got a nasty looking log for that, -(1/2)logb(b+1)


    Is that the same as: [-ln(b-1)]/[2lnb] ???


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  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    eamoss wrote:
    I'd say they want you to use the quadratic formula there


  • Closed Accounts Posts: 190 ✭✭shane0312


    d4gurl wrote:
    I cant believe people thot hons maths was easy! I couldnt do any of it!im so depressed! :( I swear it went awful! What did people get for the last part of 8? I really hated that paper!!!

    16 and the part before 32.


  • Posts: 0 ✭✭✭✭ Clay Puny Disc


    d4gurl wrote:
    I cant believe people thot hons maths was easy! I couldnt do any of it!im so depressed! :( I swear it went awful! What did people get for the last part of 8? I really hated that paper!!!

    It really wasn't easy...

    in comparsion to that sham of a 2001 paper, its the same gulf between honours and pass..

    it was a very challenging paper, and i reckon the marking scheme will reflect that..


  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    JoseJones wrote:
    Is that the same as: [-ln(b+1)]/[2lnb] ???
    Where are these natural logs comging from? Could someone who did it that way put up their technique, I'm curious.


  • Closed Accounts Posts: 137 ✭✭Inglorious


    Can somebody please confirm if a=3 was the answer to Q1 A.
    I am talking about the higher level paper.


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  • Registered Users Posts: 612 ✭✭✭JoseJones


    Raphael wrote:
    Where are these natural logs comging from? Could someone who did it that way put up their technique, I'm curious.

    give me 2 minutes


  • Registered Users Posts: 2,241 ✭✭✭Funkstard


    Has anyone ever seen/done the 95/96 past papers? Absolutely insane.

    I've realised I did 5 c) completely wrong

    Also, my friend said he was talking to his cousin, and apaprently all the honours students upped and left the room in protest at the paper. I hope there's uproar over this, because uproar = easier marking scheme


  • Closed Accounts Posts: 22 Shark-69


    That honours maths paper 1 was f**ked up........I am disgusted.....For them to put a signicant amount of Qs from 'series and sequences' in Question 5 is beyond my comprehension......I hate Question 4s with a passion......Got questions 3,6,8 fully right......but Questions 1,2 and 7 caught me out in their part c's......I got a logb answer for Q2 part c but it was x=Logb[1/sqrootof(b+1)]


  • Closed Accounts Posts: 4,564 ✭✭✭Naikon


    Raphael wrote:
    I'd say they want you to use the quadratic formula there

    Oh yeah the third term is 29:(


  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    Shark-69 wrote:
    That honours maths paper 1 was f**ked up........I am disgusted.....For them to put a signicant amount of Qs from 'series and sequences' in Question 5 is beyond my comprehension......I hate Question 4s with a passion......Got questions 3,6,8 fully right......but Questions 1,2 and 7 caught me out in their part c's......I got a logb answer for Q2 part c but it was x=Logb[1/sqrootof(b+1)]
    That's what I got alright


  • Registered Users Posts: 612 ✭✭✭JoseJones


    JoseJones wrote:
    give me 2 minutes


    here we go:


    1-b^2x=b^(1+2x)

    1-b^2x=b.b^2x

    1=(b+1)b^2x

    1/(b+1)=b^2x

    ln1-ln(b+1)=2xlnb

    [-ln(b+1)]/[2lnb]=x


  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    Inglorious wrote:
    Can somebody please confirm if a=3 was the answer to Q1 A.
    I am talking about the higher level paper.
    Did it out there and got 3, can't see any mistake


  • Closed Accounts Posts: 190 ✭✭shane0312


    Heres an answer to 2(C). Sorry about the mess it was done on paint


  • Closed Accounts Posts: 190 ✭✭shane0312


    JoseJones wrote:
    here we go:


    1-b^2x=b^(1+2x)

    1-b^2x=b.b^2x

    1=(b+1)b^2x

    1/(b+1)=b^2x

    ln1-ln(b+1)=2xlnb

    [-ln(b+1)]/[2lnb]=x
    Damn it just beat me to it:p


  • Closed Accounts Posts: 137 ✭✭Inglorious


    Raphael wrote:
    Did it out there and got 3, can't see any mistake
    Thank ya kindly.
    It was fair enough but a load of my class were complaining about it...just wanted to make sure.


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  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    JoseJones wrote:
    here we go:


    1-b^2x=b^(1+2x)

    1-b^2x=b.b^2x

    1=(b+1)b^2x

    1/(b+1)=b^2x

    ln1-ln(b+1)=2xlnb

    [-ln(b+1)]/[2lnb]=x
    Ah, so you just got the log of the 2 sides, I get it. I was more or less the same, but I did

    1/(b+1)=b^2x

    logb1 - logb(b+1) = 2x

    You also had the sign wrong in there, the - shouldn;t be in b+1, it loses that when it crosses the equals


  • Closed Accounts Posts: 190 ✭✭shane0312


    Raphael wrote:
    Did it out there and got 3, can't see any mistake
    Yeah its 3


  • Closed Accounts Posts: 190 ✭✭shane0312


    Raphael wrote:
    Ah, so you just got the log of the 2 sides, I get it. I was more or less the same, but I did

    1/(b+1)=b^2x

    logb1 - logb(b+1) = 2x

    You also had the sign wrong in there, the - shouldn;t be in b+1, it loses that when it crosses the equals

    No the minus is right hes just changing from a log fraction to two seperate values


  • Registered Users Posts: 612 ✭✭✭JoseJones


    Raphael wrote:
    Ah, so you just got the log of the 2 sides, I get it. I was more or less the same, but I did

    1/(b+1)=b^2x

    logb1 - logb(b+1) = 2x

    You also had the sign wrong in there, the - shouldn;t be in b+1, it loses that when it crosses the equals

    does it actually matter if you use loge or logb? spotted the minus, thanks.


  • Registered Users Posts: 612 ✭✭✭JoseJones


    shane0312 wrote:
    No the minus is right hes just changing from a log fraction to two seperate values


    I think he meant the minus near the start of the question...


  • Closed Accounts Posts: 190 ✭✭shane0312


    JoseJones wrote:
    I think he meant the minus near the start of the question...
    alright sorry I see..... (hangs head in shame)


  • Registered Users Posts: 6,557 ✭✭✭GrumPy


    Paper1 ordinary level was fu(kin outragous :mad:


  • Closed Accounts Posts: 902 ✭✭✭d4gurl


    shane0312 wrote:
    16 and the part before 32.

    YES I GOT 32 didnt get 16 :( cudnt figure it out!dats a plus though!here d matrix question which were simultaneous i didn look over dat part at all dat wz mean!im so annoyed!! and i wz hopin an x=asinO(teeta) wud of cum up in integration!uhh wat a mean paper mean ppl mean proof!yuk!


  • Closed Accounts Posts: 1,203 ✭✭✭Attractive Nun


    shane0312 wrote:
    Heres an answer to 2(C). Sorry about the mess it was done on paint

    Oh my God, how did I not get that? That is basically the only skill required for Applied Maths Q10. Grr...


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  • Closed Accounts Posts: 8,880 ✭✭✭Raphael


    JoseJones wrote:
    does it actually matter if you use loge or logb? spotted the minus, thanks.
    I'd say both are valid solutions in the marking scheme, tbh.

    My way:
    Solution3.jpg


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