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applied maths-linear motion q.

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  • 20-04-2007 8:27pm
    #1
    Shox
    Closed Accounts Posts: 78 ✭✭


    obvioulsy im neglecting something really obvious an this is prob a simple question.. but 2000 Q.1 (b) (i)

    When do da cars meet?

    Well if after 40 s they're both finished accelerating an both are moving at constant speed 25m/s, and One Car is 250m ahead. Does that not mean that they'll never meet!


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    #2
    cocoa
    Registered Users Posts: 1,269 ✭✭✭cocoa


    well, apparently it can never be said enough...

    read the question

    the second car is traveling in the opposite direction, from q to p.


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    #3
    Shox
    Closed Accounts Posts: 78 ✭✭Shox


    oh god, dats what a week of studyin for the oral would do to ya.. thanks, spent ages lookin at it and just never saw it. Thanks again.

    Any chance you know what to do 99 Q.1 (a) (ii)
    the power bit. i got the 744N force. Do you assume the car is starting from rest at bottom of hill and get time to get to that speed an them work out power or what???


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    #4
    cocoa
    Registered Users Posts: 1,269 ✭✭✭cocoa


    heh, i had to check skoool.ie for a def of power myself but anyway...

    P=Tv where T is the tractive force

    force right - forces left = mass * acceleration right
    therefore force right (or T even) = mass*acceleration + const resistance + weight acting downhill/left
    T = 1500*0.1 + 1500*0.2 + 1500g*1/50
    T = 1500(0.3+g/50)
    T = 744 N

    therefore, when v=20 P = 744*20 = 14880 W


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    #5
    Gangsta
    Closed Accounts Posts: 1,603 ✭✭✭Gangsta


    Shox wrote:
    Do you assume

    You don't assume anything in applied maths. Very common mistake.


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