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Maths Paper 1

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  • 04-06-2007 5:20pm
    #1
    curry-muff
    Registered Users Posts: 2,418 ✭✭✭


    Any Maths Paper 1 Questions/Answers


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    #2
    curry-muff
    Registered Users Posts: 2,418 ✭✭✭curry-muff


    I was just wondering which part of these questions make you differentiate from 1st principles as ive looked through all past papers and not once has the words differentiate from 1st principles came up


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    #3
    Lucas10101
    Closed Accounts Posts: 630 ✭✭✭Lucas10101


    Curry Muff, this type of question appears on Question 6 an 7 on Paper 1 that's all. In recent years they asked for the following:

    2005 Paper Q.7 (A)
    2004 Paper Q.6 (B II)
    2003 Paper Q.6 B(i)
    2002 Paper Q.6 B(i)

    It came up three years in a row and haven't checked 2006, so it's quite frequent but there easy marks.


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    #4
    curry-muff
    Registered Users Posts: 2,418 ✭✭✭curry-muff


    Ah right i completely ignored question 6, thanks for alerting me to it


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    #5
    curry-muff
    Registered Users Posts: 2,418 ✭✭✭curry-muff


    Right f(x) = x^2 + px +10 find f'(x)?

    How do ye do dat one???


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    #6
    Tomlowe
    Closed Accounts Posts: 131 ✭✭Tomlowe


    f'(x) = (2)x^1 + (1)px^0 + 0
    = 2x + p


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    #7
    Lucas10101
    Closed Accounts Posts: 630 ✭✭✭Lucas10101


    curry-muff wrote:
    Right f(x) = x^2 + px +10 find f'(x)?

    How do ye do dat one???

    dy/dx = 2x + p

    If you were asked find the value of P when dy/dx = 4 and x=2

    2(2) + p=4
    4+p = 4
    p=0.....or similar questions like this, I presume your doing O.L


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    #8
    justbringit89
    Closed Accounts Posts: 829 ✭✭✭justbringit89


    What u do wen
    E.G

    (4x + 12x)*


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    #9
    Lucas10101
    Closed Accounts Posts: 630 ✭✭✭Lucas10101


    (4x + 12x)*.....

    Well....you could add the 4x and 12x = 16x....I presume the star stands for a power......so 16x^3= 3(16)x^(3-1) => 48x^2

    If you were suggesting the chain rule, a typical chain rule problem would be:

    (3x^2 + 6)^4
    dy/dx =>4(3x^2+6)^(4-1)*(6x)
    24x(3x^2+6)^3


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