HL maths P.2 Q.8 B

Shox

Write the first four terms of the Maclaurin series for f(x)=Root(1+x)

Ok ive done this bit and know its right

Next part: As your expansion converges for -1<x<1, use it to evaluate Root10 correct to one decimal place...

What i did:

Root10=Root(1+x)
so 10=1+x
x=9

So i subbed this into my series an got wrong answer, naturally because x must be greater than -1 and less than 1

So i randomly tried 1/9 and got wrong answer..

Could anyone tell me the logical way t get 1/9??

Thanks

analyse this

let x=1/9 and multiply your answer by three...i think:o

root of ten=root of 9+1= root 9(1+1/9)
thats equal to 3root1+1/9

=> let x =1/9 and then multiply end result by 3

WildCardDoW

Doing Probablity, can't help you, I hate Maclaurin!

Lucas10101

ROOT 10 has to be written in the form of 1+x....

I'm not too good at these parts but 1+9= 1+9(1/9)...take root 9 =3

Thus it's 3ROOT 1+ (1/9) AND MULTIPLY your answer by 3 as it's outside the root sign.

But I think this is wrong as 9(1/9) is 1 and 1+1 is 2 which isn't ROOT 10.

eZe^

Root 10 = Root (9+1)
= 3Root(1 + 1/9)
when x=1/9 Root10 = 3f(x)...