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App Mat 1998 Newtons laws

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  • 15-06-2007 5:39pm
    #1
    Closed Accounts Posts: 78 ✭✭


    Anyone help, im stumped??


Comments

  • Closed Accounts Posts: 7,794 ✭✭✭JC 2K3


    Don't bother with it, as Oliver Murphy(guy who wrote the App Maths book) said:
    Ugh!Very tricky question because the friction exerted by A on B has an equal but opposite anti-friction which propels A forward!Should never have been asked.It’s a university question.
    http://www.discoveringmaths.com/news/belvedere/

    I never bothered to solve it at the time. It's not going to come up.


  • Registered Users Posts: 2,149 ✭✭✭ZorbaTehZ


    Solution

    U(BG) Coeffecient of friction between B and ground
    U(AB) Coeffecient of friction between A and B

    P Force pulling B forward
    S Normal Reaction of B

    R Normal reaction of A
    a acceleration

    Equations:
    P - [U(BG)].S = 55a
    S = R + 35g
    R = 20g

    If A does not slip, then [U(AB)].R = 20a

    SIMULTANEOUS!

    P = 35.75g N

    EDIT: Typo.


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