Small and probaly easy PHP problem...

Troublesome

Hey there,

The following code;

[PHP]$d = date("29/10/07");

if ($d > date("23/10/07") && $d < date("26/12/07")) {echo 'WORKS!');} [/PHP]

Will not work, any ideas?

dlofnep

Troublesome wrote: »

Hey there,

The following code;

[PHP]$d = date("29/10/07");

if ($d > date("23/10/07") && $d < date("26/12/07")) {echo 'WORKS!');} [/PHP]

Will not work, any ideas?

Not a PHP guy, but you forgot a bracket before "WORKS".

[PHP]
$d = date("29/10/07");

if ($d > date("23/10/07") && $d < date("26/12/07"))
{
echo ('WORKS!');
}
[/PHP]

Troublesome

still wont work.

dlofnep

do an else statement to make sure the code is running and print an error. then you know it's a logic problem.. to me, date looks like a string - but i'm not sure if there is variable types in php? and if it's a string, $d can't be checked to see if it's "higher" or "lower" than another string. but i don't know the return type of date. if it's an integer, then it should run.. check for that and get back to me.

Dalfiatach

The host server could be set to US date formats. Always use ISO (YYYY-MM-DD) format for dates to avoid annoying Euro/US date conversion problems.

The PHP date() and mktime() functions (and related friends) are extremely powerful and very nifty indeed if used properly. Used badly, all hell will break loose

louie

try this way:
[php]


if ( strtotime(date("2007-10-29")) > strtotime(date("2007-10-23")) && strtotime(date("2007-10-29")) < strtotime(date("2007-12-26")) ) {
echo ('WORKS!');
}
[/php]