whats wrong with this php

gnomer

im having a problem and I cannot figure out whats wrong

heres my php code:

if (substr(base64_decode($thelink), 0, 21)="http://**********.com") {
echo 'this maybe an attempt to trick the system,your account has been flagged.You cannot double link.';
}

I get

Parse error: syntax error, unexpected '=' in /home/***/public_html/***.php on line 10

i cant see anything wrong here!

EDIT: just noticed I used one = instead of two =

if (substr(base64_decode($thelink), 0, 21)="http://**********.com") {

should have been

if (substr(base64_decode($thelink), 0, 21)=="http://**********.com") {

forbairt

you're doing a numerical compare instead of a string compare ... for one ?

strcmp its a handy function ...

Webmonkey

gnomer wrote: »

EDIT: just noticed I used one = instead of two =

if (substr(base64_decode($thelink), 0, 21)="http://**********.com") {

should have been

if (substr(base64_decode($thelink), 0, 21)=="http://**********.com") {

and I take it this solved your problem?

gnomer

yeah it solved it its perfect now.

I got confused between the if and else in VB and in PHP.

I looked at the PHP 100 times and kept saying one = is ok cos its PHP,when thats olny in VB.

thanks anyways