App Math- 93 marking scheme?

grimreaper1001

Anyone got this / Know where to find it?

Cokehead Mother

I'm pretty sure there was some point before which the department didn't publish marking schemes. I think it might've been some year in the 90's. So there mightn't even be any teachers with, and it certainly can't be found on the net. Although this information is coming from a very vague memory of a post on boards which could have been a load of bull****...

I take it you don't care about the actual marks given and whatnot and just want the solution? You could post the questions you need solutions of and someone here'd be happy to help you out I'm sure.

TheDriver

Oh theres marking schemes to the very beginning, I have as far as 1980 in the filing cabinet in school

grimreaper1001

I'll post it up tomorrow. Thanks

alan4cult

A bit of History,
Marking Schemes were only made available to teachers and schools in 1995. Before this only the examiners had a copy of the marking schemes and of course anybody who had a photocopy of the examiners' ones. To compensate for the lack of solution availablity many third parties published full solutions for subjects like maths, app maths and physics.

If you're looking for help on a particular question post it up here and we'll sort you out.

grimreaper1001

2003 Q3 HL
{a} A particle is projected on a horizontal plane with initial velocity u at an angle beta to the horizontal. If the range of the projectile is three times the greatest height, prove that tan beta = 4/3

{b} A particle is projected up an inclined plane with initial speed u. The line of projection makes an angle of 30degrees with the plane and the plane is inclined 30degrees to the horizontal. (The plane of projection is vertical and contains the line of greatest slope.) The particle strikes the plane at an angle theta,theta < 90degrees (i.e. theta is the landing angle).

(i) Express the velocity and displacement of the particle after t seconds in terms of unit vectors i and j along and perpendicular to the plane, respectively.

(ii) calculate theta


p.s. there were no diagrams and this is the original text, except there was a degrees symbol instead of degrees and and proper symbols for beta and theta.

timmywex

grimreaper1001 wrote: »

2003 Q3 HL
{a} A particle is projected on a horizontal plane with initial velocity u at an angle beta to the horizontal. If the range of the projectile is three times the greatest height, prove that tan beta = 4/3

{b} A particle is projected up an inclined plane with initial speed u. The line of projection makes an angle of 30degrees with the plane and the plane is inclined 30degrees to the horizontal. (The plane of projection is vertical and contains the line of greatest slope.) The particle strikes the plane at an angle theta,theta < 90degrees (i.e. theta is the landing angle).

(i) Express the velocity and displacement of the particle after t seconds in terms of unit vectors i and j along and perpendicular to the plane, respectively.

(ii) calculate theta


p.s. there were no diagrams and this is the original text, except there was a degrees symbol instead of degrees and and proper symbols for beta and theta.

Just did this q out 2days ago

Dontn have the copy with me at this min, but ill have it later tonight and post the answer then, fairly straight forward projectiles q tbh.

Where you from grimreeper outta interest?

grimreaper1001

Trim, Co. Galway

Cokehead Mother

I'll post (b) in a few minutes.

timmywex

grimreaper1001 wrote: »

Trim, Co. Galway

Fair enough, just our class got that question on tuesday so just thought it was a coincidence!!

cokehead mother, howd ya get the answer to come up all fancy like that?

Cokehead Mother

Okay so this diagram is... awful, but you might be able to get the general idea... maybe. g is the acceleration due to gravity, and I've resolved the vector so that there's components parallel to the x and y axes. Also I used x and y in my solution and then changed to i and j which was pointless so yeah, sorry about that.





I wish I knew what the answer was cause I'm not great at applied maths, but that looks okay I think...

grimreaper1001

timmywex wrote: »

Fair enough, just our class got that question on tuesday so just thought it was a coincidence!!

cokehead mother, howd ya get the answer to come up all fancy like that?

LOL, why where you from? If you say Trim I will be scared.

timmywex

grimreaper1001 wrote: »

LOL, why where you from? If you say Trim I will be scared.

Nah, its wexford for me!

grimreaper1001

Thank you so much cokehead mother, I would never have figured this out myself. I didn't think anyone would respond so fast.

Cokehead Mother

I'm not sure that's right at all. It seems ok to me but I dunno.

grimreaper1001

Thanks ever so much - I'm sure it's right, and if it ain't, it's still an answer.

MathsManiac

I've looked through Cokehead's solution and it looks corrrect to me all the way down to the second last line. i think there's a 2 missing from the denominator of vx. Fixing this gives tan(theta)=sqrt(3), giving theta=60, which has the benefit of being a nice answer!

(And by the way, if that diagram was drawn freehand with a mouse, it's not half bad!)

Cokehead Mother

Yep, v_x should definitely have a two in the denominator.