c++ object array declaration

theliam

ok say i have a class circle with 3 parameters. i'd declare a variable of type circle - circle c1(a, b, c) i think..

but how do i declare an array of circles if it takes parameters?

lynchie

Well without doing it dynamically at runtime.. you can do it as follows

Circle* myArray[3];

Circle c1(1,2,3);
Circle c2(2,3,4);
Circle c3(4,5,6);

myArray[0]=&c1;
myArray[1]=&c2;
myArray[2]=&c3;

fasty

That's all well and good until c1, c2 and c3 go out of scope... Make sure you give the Circle class a valid copy contructor and operator= functions (Google this stuff, it's easy and chances are your compiler will generate default versions of these functions for you that'll work fine unless you've got dynamic memory allocation or the like in your Circle class) then...

Circle myArray[3];
myArray[0] = Circle(1,2,3);
myArray[1] = Circle(2,3,4);
myArray[2] = Circle(4,5,6);

DublinDilbert

fasty wrote: »

Circle myArray[3];
myArray[0] = Circle(1,2,3);
myArray[1] = Circle(2,3,4);
myArray[2] = Circle(4,5,6);

Will that not try call the default constructor, if available upon the declaration Circle myArray[3];

Its not major as the next 3 calls will assign 3 new static objects to the objects in the array.


You could also try to create them dynamically:-

Circle *myArray[3];
myArray[0] = new Circle(1,2,3);
myArray[1] = new Circle(2,3,4);
myArray[2] = new Circle(4,5,6);

fasty

Yeah it would call the default constructor alright!