ANOTHER silly maths question..

We

ye so, functions and graphs this time..
Now this should be easy enough.. but I'm silly, so apparently not so easy for me ;p

The graph of the function f(x) = x^2 + bx + c is shown..
Find the values of b and c...

if the graph isn't clear enough, the curve goes through (0,0) and (5,0)






thanks homies

Jack Sheehan

Put in the values, form two equations and use similtanious equations to get a result?

We

:facepalm: ... thanks jack, dunno why I didn't sub in both x and y values.. I just subbed in the x value for both points and when it didn't look how I expected it to, I came here ;p laziness I guess ^_^

Jack Sheehan

No Worries.

383Ger

The curve x^2+bx+c cuts the x-axis at 0 and 5, thus x=0 and x=5 will solve the equation x^2+bx+c=0

Substituting:
(0)^2+b(0)+c=0
0+0+c=0
c=0

Now substituting x=5
(5)^2+b(5)+0=0
25+5b=0
5b=-25
b=-5

We

just did it there and got same answer, cheers lads