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Solving Equilibrium Problem

  • 15-05-2009 9:52pm
    #1
    Closed Accounts Posts: 25


    Please help me solve this question:-

    The diagram show rulers balanced at their centres of gravity. What is the value of Y? (the answer on my text book is y = 4.5N but I cannot arrive at this answer)


    <
    25cm
    > l<---15cm---><
    15cm--->
    _@________________l___________@_____________@___
    6N...........................l.................1N....................Y




    Your assistance is appreciated.


Comments

  • Moderators, Sports Moderators Posts: 27,489 Mod ✭✭✭✭Podge_irl


    In order for the ruler to be balanced you need the torque on either side of the pivot to be equal. Torque is given by (distance)x(force). The torque on the left is thus 6x(0.25). Remember you're working in SI units where 1 metre = 1, and so 25 centimetres = 0.25. You need to equate this to the force on the right, which will give you a very simple linear equation to solve for y.

    6x(0.25) = 1x(0.15) + Yx(0.3)

    The answer to this (which you should be able to work out easily) is Y = 4.5


  • Closed Accounts Posts: 25 Tikkal


    Thank you for your reply but although I am doing this equation I am coming up with a different answer:-


    1.5=0.15+0.30y

    1.5=0.45y

    What am I doing incorrect?


  • Moderators, Sports Moderators Posts: 27,489 Mod ✭✭✭✭Podge_irl


    You're adding the right hand side wrong. You have 0.15 + 0.3Y, that does not equal 0.45Y. You need to keep all factors of Y seperate from all terms that have no Y in them. Instead you take the 0.15 over to the other side and the equation becomes
    1.35 = 0.3Y
    which gives you the right answer.


  • Closed Accounts Posts: 25 Tikkal


    You are a legend. The lightbulb finally went on! Solved. Whew. Thank You. Have a good weekend.


  • Registered Users, Registered Users 2 Posts: 861 ✭✭✭Professor_Fink


    Tikkal wrote: »
    Please help me solve this question:-

    The diagram show rulers balanced at their centres of gravity. What is the value of Y? (the answer on my text book is y = 4.5N but I cannot arrive at this answer)


    <
    25cm
    > l<---15cm---><
    15cm--->
    _@________________l___________@_____________@___
    6N...........................l.................1N....................Y




    Your assistance is appreciated.

    You need to balance the torque. Torque for each mass is simply (distance from pivot)*mass. On the left we have 1.5 Nm, while on the right we have 0.15Nm + Y*0.3m. Since the two sides must be equal, Y=(1.5-0.15)N/0.3 = 4.5N.


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  • Registered Users, Registered Users 2 Posts: 861 ✭✭✭Professor_Fink


    Sorry, I missed the replies.


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