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Higher Level Maths 2009(Paper 1): How was it for you?

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  • Closed Accounts Posts: 407 ✭✭OxfordComma


    .:FuZion:. wrote: »
    Bollox I did it again and got 4/3 lol.


    I got 1/2 the first time and then re-did it at the end of the exam. I'd made a mistake with signs...


  • Closed Accounts Posts: 5,109 ✭✭✭QueenOfLeon


    Pygmalion wrote: »
    6 part B(ii) I got t^3 + t for the speed and 130m/s at 5 seconds.

    Balls. Units of measurement. Damn :rolleyes:


  • Registered Users Posts: 2,604 ✭✭✭xOxSinéadxOx


    Balls. Units of measurement. Damn :rolleyes:

    is that -3 yeah? don't think I put it


  • Closed Accounts Posts: 5,082 ✭✭✭Pygmalion


    Balls. Units of measurement. Damn :rolleyes:
    I actually wondered whether you'd lose marks for it myself, it does say on the exam that you need to put it in but I never remember my teacher saying anything about it, and I've only really heard it's a big deal for Physics, though maybe it's just because it's rare to get a question with specific units in Maths.


  • Closed Accounts Posts: 4 HunterBK21


    BLARG wrote: »
    (A^3)^14 = A^17

    (A^3)^14=A^42
    A^3 X A^14=A^17

    For me,
    1. Was fine, got two answers for c(ii) though
    2. grand except for c(ii)
    3. I did De Moivre right, but it didnt work out.
    6. Did a very weird proof for c(ii), hopefully its right
    7. Perfect
    8. Best integration question ever.


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  • Closed Accounts Posts: 5,109 ✭✭✭QueenOfLeon


    is that -3 yeah? don't think I put it

    No idea, hopefully just a slip? :rolleyes:

    Ok everyone, for maths paper 2, dont forget your cm/m etc for trig and question 8!

    This is as much for my benefit as anyone else :p


  • Posts: 0 ✭✭✭ [Deleted User]


    Pygmalion wrote: »
    6 part B(ii) I got t^3 + t for the speed and 130m/s at 5 seconds.
    v = ds/dt.
    How exactly did you get t^3 + t??

    I make it t/sqrt(t^2 +1)

    5/root 26 metres/second, yeah?


  • Registered Users Posts: 942 ✭✭✭whadabouchasir


    Pygmalion wrote: »
    , and I've only really heard it's a big deal for Physics,
    You only lose 1 mark if you don't have the measurements ii physics.It doesn't say that marks will be lost if you don't include measurements, just that you should.


  • Closed Accounts Posts: 106 ✭✭JW91


    ya if you do physics (which i do) you'd never forget to put in the units because it's vital in physics.

    In fairness it does say on the front of the paper to put in units where neccesary so I'd say they'll dock you 3 marks probably.


  • Closed Accounts Posts: 609 ✭✭✭GA361


    .:FuZion:. wrote: »
    Not a bad paper.

    1(C): C = B + 1???
    2(C): I got r = q(p^2)n or something. Dont think its right. And q = (+-) 6?


    Well I got c=3b^(squared) + 1
    Any one else gat that ?
    Firstly I divided the line by x-c+1 and then let x=c-1 and equated them . . . . anyone else do this?


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  • Registered Users Posts: 549 ✭✭✭Jam-Fly


    Pretty sure these questions are right, but I'd like to know for sure

    Q1a) x/y = 3/2

    I cross multiplied. I assumed you can do this here. Wasn't sure if maybe I shoulda multiplied by the (denom)^2 or by the conjugate or summin

    Q2bi) I said: f(x) => Two imaginery roots. g(x) => Two equal real roots. h(x) = > Two unequal real roots

    I understand the concept and all that, but is my answer too vague??!

    Q2ci) I got r = (n.q^2)/p(n^2+2n+1)..anyone get anything similar to this?

    Q3bi) A^3 = [-1 0 0 -1] [matrices]

    Q4ci) ar^2m
    ii) ar^m-0.5 are these right?


    also did Q5 and Q7 but don't have many answers written to these.

    Overall, good paper. Figured I got 225/300 at best, 165ish/300 at worst


  • Registered Users Posts: 2,604 ✭✭✭xOxSinéadxOx


    GA361 wrote: »
    Well I got c=3b^(squared) + 1
    Any one else gat that ?
    Firstly I divided the line by x-c+1 and then let x=c-1 and equated them . . . . anyone else do this?

    can't remember what the question was. I got either you answer or the other guy's one though :)


  • Registered Users Posts: 4,532 ✭✭✭WolfForager


    We got paper 2!

    I joke >_>

    Anywho..

    Q1 (c) didn't work out properaly at the end...
    Q2 (c) heh?
    Q3 (c) no one in my class learned demoivre's therom => screwed.
    Q6 (c) (ii) haha...
    Q7 (c) (iii) i did it but i don't think it was 100% correct.
    Q8 (b) (ii) mental block ftl.


  • Posts: 0 ✭✭✭ [Deleted User]


    Q4ci) ar^2m
    ii) ar^m-0.5 are these right?

    They're right, I think.
    [/QUOTE]


  • Closed Accounts Posts: 5,109 ✭✭✭QueenOfLeon


    Jam-Fly wrote: »
    Pretty sure these questions are right, but I'd like to know for sure

    Q1a) x/y = 3/2

    I cross multiplied. I assumed you can do this here. Wasn't sure if maybe I shoulda multiplied by the (denom)^2 or by the conjugate or summin

    Q2bi) I said: f(x) => Two imaginery roots. g(x) => Two equal real roots. h(x) = > Two unequal real roots

    I understand the concept and all that, but is my answer too vague??!

    Q2ci) I got r = (n.q^2)/p(n^2+2n+1)..anyone get anything similar to this?

    Q3bi) A^3 = [-1 0 0 -1] [matrices]

    Q4ci) ar^2m
    ii) ar^m-0.5 are these right?


    also did Q5 and Q7 but don't have many answers written to these.

    Overall, good paper. Figured I got 225/300 at best, 165ish/300 at worst

    Exactly the same, except 4, i dont do it. Looks evil :rolleyes:


  • Registered Users Posts: 11 Pixiesticks


    • For question 1c I got c=b+1...anyone else?
    • 2c(ii) I got the thing for r from the question before, subbed in 5 for n and 1 for p, and then said it was bigger or equal to one cause it's a positive integer? and I got q was root 5 over 6 or something o.O???
    • anyone else get stuck on 4c(iii)???
    • for 6c(ii) I said dy/dx wasn't equal to zero, so no turning points, so there couldn't be perpendicular??
    • and 7c was ok once you figured out what they wanted I thought? I hope...I just subbed in 2.5 and that was >0 so the root was between 2 and 0??


  • Posts: 0 ✭✭✭ [Deleted User]


    For 2 c (ii)
    I said the set of all q such that q = 5^n, where n is an element of N-subzero and n /= 2.

    Hope it's right.


  • Closed Accounts Posts: 5,082 ✭✭✭Pygmalion


    v = ds/dt.
    How exactly did you get t^3 + t??

    I make it t/sqrt(t^2 +1)

    5/root 26 metres/second, yeah?
    Yeha I think you're right, I got:
    s = (t^2 + 1)^1/2;
    ds/dt = 1/2(t^2 + 1)(2t)
    ds/dt = t(t^2 + 1) = (t^3 + 1)
    
    But Should have been:
    s = (t^2 + 1)^1/2;
    ds/dt = 1/2(t^2 + 1)[B]^-1/2[/B](2t)
    ds/dt = t/(t^2 + 1)^1/2
    


  • Closed Accounts Posts: 5 Jackstone


    They asked you that Anne's root is less than 2.5 but it was 2.66, which in turn was greater than Barry's. I know I'd my method right.

    Thats what confused me!? A woman had a bigger root than a man?!

    but no.....all jokes aside....i failed badly


  • Posts: 0 ✭✭✭ [Deleted User]


    Jackstone wrote: »
    Thats what confused me!? A woman had a bigger root than a man?!

    but no.....all jokes aside....i failed badly

    It meant her first approximation, before she used the method, which was 2. That had me for a while in the exam hall.


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  • Closed Accounts Posts: 5 ciaran brady


    anyone no how you prove asymtotes tangents are parallel?


  • Registered Users Posts: 168 ✭✭RayCarley


    Looks like 2c was the typical A blocker then. I really didn't know what to do. Although one of my mates said that he got: "q is divisible by 6", which sorta makes sense since it's looking for a set of values, not a range. So then anytime q is a multiple of 6 you get the right roots.

    It's a pity I put down something like 0<q<36/5

    Meh, I think I managed to get 4c out as an extra question so I think it's all good.


    As for 7c, I though it was quite straight forward... just had to remember that part (ii) was talking about their first approx (x1=2 and x1=3), then it was grand.


  • Registered Users Posts: 4,893 ✭✭✭Davidius


    anyone no how you prove asymtotes tangents are parallel?

    You mean 6(c)?

    To prove that no two tangents are perpendicular you have to prove that the product of the slopes of any tangents cannot be -1. (For perpendicular lines: m1*m2 = -1)

    The slope of a tangent at a point is dy/dx so you pretty much have to prove that dy/dx is always negative or positive seeing as negative*negative != -1 and positive*positive !=-1.

    PS. ^That's not my Death Star. :pac:


  • Registered Users Posts: 168 ✭✭RayCarley


    Davidius wrote: »
    PS. ^That's not my Death Star. :pac:

    Ah but you only have the incomplete model, hardly worth the effort really :p


  • Registered Users Posts: 156 ✭✭AndyWhite


    for 1.c did anyone else get c=b^2 - 1?
    I wasnt sure if that was right and i didnt have time to check it again.

    Also, i got q= 6(r/5)^1/2 r>0 for c ii.
    that look at all right to anyone?

    Wasnt too bad an exam overall. i reckon i didnt get less than a B2...
    ...i hope!


  • Closed Accounts Posts: 23,316 ✭✭✭✭amacachi


    Davidius wrote: »
    I just realised that I never sketched the curve.

    Le bollox.

    Same here.



    Does anyone know if changing a sign from one line to the next by mistake is a slip or a blunder?


  • Registered Users Posts: 156 ✭✭AndyWhite


    amacachi wrote: »
    Same here.



    Does anyone know if changing a sign from one line to the next by mistake is a slip or a blunder?

    Im pretty sure they regard a change in sign as a blunder usually. I could be wrong there and i think it can vary too but thats what i heard before.


  • Registered Users Posts: 1,019 ✭✭✭carlmango11


    The only question I couldn't get an answer (be it right or wrong) for was the anne and barry part of q7. After reading a few posts I realize how easy it was
    :(:(:(:(:(


  • Registered Users Posts: 521 ✭✭✭Prowetod


    Anyone have answers to 3(b)?

    TY


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  • Closed Accounts Posts: 2,836 ✭✭✭TanG411


    I scraped a pass :D

    Got all of integration out so I was happy. Algebra was a fail for me (Really disappointed tbh)

    COmplex numbers deadly. Q6 was okay and Q7 was tricky but doable.

    Can wait for paper II


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