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Statistical Maths Problem in Psychology

  • 20-11-2009 3:29pm
    #1
    tootyflutty
    Registered Users, Registered Users 2 Posts: 782 ✭✭✭


    Might be the wrong place to ask, seeing as it's more maths based but just wondering if any one can help me with a psychology assignment for my statistics lectures.

    I need to find the values of N and ΣX for the scores in the following frequency distribution table:

    X - f
    11 - 2
    5 - 4
    3 - 1
    2 - 2

    Even if someone could show me how to do the first one I would be so grateful!
    I'm really at a loss with this. :confused:


Comments

  • #2
    Valmont
    Registered Users, Registered Users 2 Posts: 5,857 ✭✭✭Valmont


    Well I take ΣX to mean the "sum of X" (Σ being the summation operator) so I would add up 11, 5, 3 and 2... to give me 21. I'm not sure about the N though? I would imagine it is just the sum of the numbers in the F column although I'm not certain.

    An applied statistics book is great to have when studying psychology. I would recommend Hinkle, Wiersma, & Jurs (2003) Applied statistics for the behavioral sciences, 5th edition.


  • #3
    jaysond
    Closed Accounts Posts: 10 ✭jaysond


    Did you mean small n instead of N? If so, small n would be 4 for both X and f and they each have 4 elements in their lists.


  • #4
    DeVore
    Business & Finance Moderators, Entertainment Moderators Posts: 32,387 Mod ✭✭✭✭DeVore


    I suspect Big N is the "average" while "f" is the frequency??

    If thats the case then you have 2 occurences of the value 11, 4 occurance of the value 5 etc etc.

    so, to find the average, you multiply 11x2 and 4x5 and 3x1 and 2x2 and add up the result (22+20+3+4 = 49) and then divided by the total number of occurances (the sum of f, that is 2+4+1+2 = 9). So N would be 49/9 (whatever that is)...

    ALTERNATIVELY (since that seems very complex compared to being asked to simply sum X)... Big N could be the average of X which would be 11+5+3+2 / 4 = 21/4

    I think you need to give us some more info before we can answer your question :)

    DeV.


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