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Parse XML from Url

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  • 28-02-2010 11:44pm
    #1
    Kenno90
    Registered Users Posts: 3,184 ✭✭✭


    Hi All,
    I found an XML web page(which updates every few minutes) on the internet and i want to fetch the data on that XML page to my own website(localhost)

    Does any one have any html or php code that will take the xml data from the url and display it on my webpage

    i've tried a few methods but i'm getting nowhere

    Thanks


Comments

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    #2
    Webmonkey
    Registered Users Posts: 9,579 ✭✭✭Webmonkey


    Why don't you get the XML and parse it? - How do you want it displayed?


  • Options
    #3
    Evil Phil
    Registered Users Posts: 7,468 ✭✭✭Evil Phil


    The forum charter would be a good place to start, read the section regarding asking questions.


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    #4
    Kenno90
    Registered Users Posts: 3,184 ✭✭✭Kenno90


    Sorry Guys, will try this again:rolleyes:

    OK the problem is i found an XML page on the internet that updates it's self every few minutes.
    I want to add the whole xml in to my own webpage.

    i've tried the following codes 
    (1) 
<?php 
$xml = file_get_contents('http://www.[COLOR=Red]Websitehere[/COLOR].xml'); 
echo"$xml";
?>

and

(2)
<?php 
$fetch_url = "http://www.[COLOR=Red]Website here[/COLOR].xml"
$xml = simplexml_load_file($fetch_url) or die("error"); 
echo"$xml";
?>
    When i use either of these codes i get no errors just a blank screen that does nothing.

    Have any of you guys experience using xml across domains and help me out,thanks.


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    #5
    Webmonkey
    Registered Users Posts: 9,579 ✭✭✭Webmonkey


    Not sure if I know exactly what you want. You just want the XML outputted the same as you have there?

    You may need to set the http headers then to specify that it's XML content

    Try this:

    [php]
    <?php
    header ("Content-Type:text/xml");
    $xml = file_get_contents('http://www.Websitehere.xml');
    echo"$xml";
    <?php>
    [/php]

    (I haven't tested this)


  • Options
    #6
    Kenno90
    Registered Users Posts: 3,184 ✭✭✭Kenno90


    Webmonkey wrote: »
    Not sure if I know exactly what you want. You just want the XML outputted the same as you have there?

    You may need to set the http headers then to specify that it's XML content

    Try this:

    [php]
    <?php
    header ("Content-Type:text/xml");
    $xml = file_get_contents('http://www.Websitehere.xml');
    echo"$xml";
    <?php>
    [/php](I haven't tested this)

    Ye all i want to do is output the xml to my webpage and then once i get that working i will see if i want to display certain parts of the xml.
    Thanks for your help will try your code ;)


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    #7
    Webmonkey
    Registered Users Posts: 9,579 ✭✭✭Webmonkey


    Your original code is probably outputting it alright but browser won't render it. If you go view source, it probably there.


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    #8
    Kenno90
    Registered Users Posts: 3,184 ✭✭✭Kenno90


    nah not in the source code on the browser, will keep trying though:rolleyes:


  • Options
    #9
    ron_darrell
    Users Awaiting Email Confirmation Posts: 351 ✭✭ron_darrell


    I know you want to use PHP but this way will work too (some parsing done so please feel free to change as required). Just add a timeout to reference the displayInfo function every interval to keep updating the page

    HTML file 
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<head>
    <title>Book</title>
    <script type="text/javascript" language="javascript" src="book3.js"></script>
    <link rel="stylesheet" type="text/css" href="book.css"/> 
</head>
<body onload="javascript:displayInfo('book.xml')">
    <div id='details'></div>
</body>
</html>

    Javascript file 
    var xmlhttp;

function displayInfo(filename) {
	xmlhttp = GetXmlHttpObject(); // create an object to handle the XML Http Request
	if(xmlhttp == null) { // If the browser can't handle XML Http requests
		alert ("Your browser does not support AJAX!");
		return;
	}

	xmlhttp.onreadystatechange = processReqChange;	// The command that will handle changes in the state of the XMLHttp request object
	xmlhttp.open("GET", filename , true);			// The XML file we are going to interrogate
	xmlhttp.send(null);								// Start the data stream
}

function processChange() {
	var xmlDoc = null;								// Create an object to handle the XML object coming back from the file
	if(xmlhttp.readyState == 4) {					// Only do something if the readystate is 4
		xmlDoc = xmlhttp.responseXML;				// Store the returned XML object in our local object
	}
	if(xmlDoc != null) {							// Make sure something came back
		var theString;								// To hold the generated HTML

	 	for (i = 0; i < xmlDoc.documentElement.childNodes.length; i++)	// Go through each of the main nodes of the parent node
		{
			// If element has no child node, ie. <isbn>
			if (xmlDoc.documentElement.childNodes[i].childNodes.length == 1) 
			{
				var bookXMLDetails = "<span style=\"background-color:green;\">" + xmlDoc.documentElement.childNodes[i].firstChild.nodeValue + "<span>";		  // Retrieve the data of the node and put it in a green span
				document.getElementById('details').innerHTML += bookXMLDetails + "<br />";	// Display to the screen
			}
			// If the element has child nodes
			if (xmlDoc.documentElement.childNodes[i].childNodes.length > 1) 
			{
				currentNode = xmlDoc.documentElement.childNodes[i];	// Store the index of the node
				var size = currentNode.childNodes.length;			// Find out how many children it has
				for (j = 0; j < size; j++)							// Loop through each child
				{
					if(currentNode.childNodes[j].nodeType == 1) {	// If the node type is non text
						subNode = currentNode.childNodes[j];		// Then there are subnodes
						var subSize = subNode.childNodes.length;	// Find out how many
						for(k=0;k<subSize;k++) {					// Loop through each one
							// Put it in a red span
							var bookXMLDetails = "<span style=\"background-color:red;\">" + subNode.childNodes[k].nodeValue + "</span>";
							// Display to the screen
							document.getElementById('details').innerHTML += bookXMLDetails + "<br />";
						}											// End Loop
					}	// End If
				}	End Loop
			}	// End If
		}	// End Loop
	} // End If
} // End Function

function GetXmlHttpObject() {
	if(window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
		return new XMLHttpRequest();
	}
	if(window.ActiveXObject) {  // code for IE6, IE5
		return new ActiveXObject("Microsoft.XMLHTTP");
	}
	return null;
}

    The XML file (replace reference to this file with the URL for the page you're interested in) 
    <?xml version="1.0" encoding="utf-8" ?>
<book edition="3" year="2004">
  <isbn version ="10">0596007647</isbn>
  <isbn version ="13">0596007648</isbn>
  <title>XML in a Nutshell</title>
  <subtitle>A Desktop Quick Reference</subtitle>
  <tags>
    <tag>reference</tag>
    <tag>xml</tag>
  </tags>
  <author id="eh120">
    <name>Damien Gannon</name>
  </author>
  <author id="eh125">
    <name>Gretta Davern</name>
  </author>
  <publisher>Rielly Media, Inc.</publisher>
</book>

    Hope that helps,
    Regards,
    RD


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    #10
    Kenno90
    Registered Users Posts: 3,184 ✭✭✭Kenno90


    Thanks Ron,

    Your code helped,:D


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