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Foundation Maths Paper 2.
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13-06-2010 8:49pm#1
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(c) The line K has equation y = 3x + 2 .I'm weak at everything lol. I'm currently stuck on q4 part c 2007
I managed to do everything so far
The line L has equation 2y = 6x −1.
The point c has co-ordinates (1, 5).
(i) Show that the point c lies on the line K.
For this, you substitute (1, 5) into the equation of the line.
You do this because if the point lies on the line, it will statisfy the equation.
That means you replace y with either 1 or 5 and you do likewise with x.
So, here goes:
y = 3x + 2
5 = 3(1) + 2
5 = 3 + 2
5 = 5
THEREFORE THE POINT (1,5) is on the line K.
(ii) Write down the slope of K.
If you know the equation of a line, which is in the log tables it will say: y - y1 = m(x -x1)
m = slope
K = y = 3x + 2, as you can see, K is in the same format.
So from K we can see the slope is 3
(iii) Write down the slope of L.
Applying the same thinking and principle of part (ii) we can see the slope for L is 2y = 6x - 1
To symplify this we must divide by 2, because the y value must be y only, with no number.
So, we get, y = 3 - 1/2
Therefore the slope for L is 3
(iv) Are the lines K and L parallel? Explain your answer
If lines are parallel, the slope of the two lines will be the same.
Slope K=3
Slope L=3
Therefore they are parallel
:D
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Carsinian Thau wrote: »No problem at all. Happy to help.
Do you want a more detailed thing for part c? (Or anything else for that matter?)
More deataiiled for part c
I have not studied maths all year and that damn part c comes up every year so I really just want to be able to do it...:(0 -
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Look at the diagram they gave us for this too:
Seeing as we have been asked to calculate the bird's vertical height above the ground we can construct a right angled triangle. We are told that the bird flies off at an angle of 25 degrees and that (s)he flies 40 metres from the starting point. This length is the hypotenuse as it is opposite the right angle (90 degrees).
From this we can work out the height as the sine of the angle they give us (25 degrees) will be equal to the length of the height over the distance it flew. This is because the length of the height is the side opposite the angle and the distance it flew is the hypotenuse.
Therefore, sin 25 = Height / 40
Multiply both sides by 40 to remove the fraction:
40 * sin 25 = Height
The sine of 25 degrees = 0.422618262 (Make sure your calculator is set to degrees!!!)
So, Height = 40 * 0.422618262
Therefore, Height = 16.9047305 metres.
Asked for answer correct to nearest metre means (in this case) rounding up to give an answer of 17 metres.0 -
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God I feeL so screwed for maths. I don't get anything in question 1 but simosons rule like i never know the part a or c... It always confuses the crap outta me... I can hardly do 4 questions...:(
You really will be fine. The examiners are there to try and get you to pass. Just do your best and it really will be ok in the end.
Unfortunately, I can't help you with the Simpson's Rule thing, I did HL and it didn't seem to be on our course.
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Carsinian Thau wrote: »You really will be fine. The examiners are there to try and get you to pass. Just do your best and it really will be ok in the end.
Unfortunately, I can't help you with the Simpson's Rule thing, I did HL and it didn't seem to be on our course.
I really hope so I just want to pass if I fail maths again my parents will never speak to me again... I'm so nervous right now I can't sleep.0
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