Maths HL Paper 2

muffinz

eoins23456 wrote: »

oh right ok haha just confused the hell out of me there:p

hahah sorry sorry sorry :L i did the trig question with the tan 0 = m1 m2 equation, and then i had 2 minutes to spare in which i went back to finish that vectors question, and bolloxed it up in my nervous-rushy-state!! i was the last to finish in my whole centre, the examiner kept sending me daggers :L

dara92cove

Emm... paper was so nice, compared to paper 1 i think.....
o n btw,
Project maths was apparently a joke,
maths professors on the raido said if that's the way its going,
were going to be the laughing stock of Europe
one question apparently was the exact same as q4 on the ordinary paper...:(


did any1 else get these???

Q1 (a) (x-3)^2 + (y+4)^2......
(b) centre (4,3) radius 3
ii) k -17 or -47
(c) (x-6)^2 + (y-2)^2 = 20

Q2 (a) C= (-i,-3j)
(b) |v|=squared root of:(1+k^2) and u.v= -2+k
ii) k 7 or 1
(c) q = c +1/2 a
ii) AQ = c -1/2 a
iii)yea oc = cr

Q3 (a) a=8
(b) P: (-k/4 , 0) and Q: (0 , k/5)
ii) k = 20 and -20
(c) x"- y" = m(x"+Y") + 2c
ii) m = -1

Q6 (a) both are red : 1/6
(b)
(c) 6 times more likely

Q7 (a) 1,021,020 > 1,000,000
(b) 7/20
ii) 1/40
iii) 19/24
(c) u = 3a and o = squared root of: (2a^2)
ii) mean = 9a+5 and standard deviation = squared root of: (18a^2)

and Q8.....:( was a diastor, i was always going to be...
but did anybody get:
(b) i) 18p - 2p^3


????????

Reckle

paper 2 was grand for me could do a good few questions and i felt more confident on paper 2 than paper1
i was expecting a difficult paper as people on this said how easy p1 was and i struggled with it!
ahh still hoping for d3 only though!!

eoins23456

straight_As wrote: »

Leaving cert maths has gone to the shitter.

That paper doesn't compare to the early 2000's.

2001 paper was piss i reckon and 2004 wasnt that hard either.dont think the standard has paper has gotten any easier

karen-xxxxx

Reillyman wrote: »

Anyone else get these answers?

1.(b)(ii) [latex] k=-17, k=-47[/latex]


4.(c)(iii) [latex] r=\frac{bc}{2a}[/latex]


5.(c)(ii) [latex] x= 10^{\circ}, 70^{\circ}, 130^{\circ}, 190^{\circ}, 250^{\circ}, 310^{\circ} [/latex]


6.(a) [latex] \frac{2}{7} [/latex]


8.(a) [latex] x\log_e x -x+c [/latex]

(b)(ii) [latex]12\sqrt3 [/latex]

(c)(ii) [latex]\frac{331}{1440} [/latex]

yap!

eoins23456

muffinz wrote: »

hahah sorry sorry sorry :L i did the trig question with the tan 0 = m1 m2 equation, and then i had 2 minutes to spare in which i went back to finish that vectors question, and bolloxed it up in my nervous-rushy-state!! i was the last to finish in my whole centre, the examiner kept sending me daggers :L

like everyone stayed till the end in our centre.know what ya mean made a mess of the my last probabiliy question n kept writing more as the examiner turned his back to collect despite having said stop writing haha.prob adding to my own detriment :O

Pimptastic

mahonykid wrote: »

if u doubled ur answer at the end you wouldnt lose any

Fraid not

3_BOoYA_X

Can i join the c3 bandwagon ?

Actually was such a nice paper2, is it a bad thing that i enjoyed it? :rolleyes:

psychoduck

this paper was a disgrace for me, my brain simply didnt work at all
I couldnt do my favourite question, Q4 part c) at all! nothing worked out!
In 5c) ii I messed up the angles in the end, but the procedure was right
and Q8, oh dear... in part a) i integrated dx as 1 instead of x, my maths teacher said it would be only 3 points, but still...
and for the part b) i got the area 81, and i still dont know where i went wrong!

(i) the expression for the area was 18p-p^2, wasnt it?
(ii) so i differentiated it and got
18 - 2p = 0
p = 9
and then when put into the formulae for the area i got:
A = 162 - 81 = 81

Please, tell me, what I did wrong, because its killing me!
...do you think I can still get an A1 considering the paper 1 went smoothly enough?

eoins23456

3_BOoYA_X wrote: »

Can i join the c3 bandwagon ?

Actually was such a nice paper2, is it a bad thing that i enjoyed it? :rolleyes:

ur allowed enjoy the nice ones n forget about the bad ones

randylonghorn

Ok ...

Two general reminders:

1) Personal abuse to another poster is not acceptable on this site.

2) Txtspit is not welcome either.

KealanOCarroll

Heres my answers: Looking similar to most already posted so its lookin like im gettin at least a C3...UL bonus points yupouttadat:D

1)
a) (x-3)^2 + (y+4)^2 = 15 (not 17?:()

b) i) Centre (4,5) Radius 3
ii) k= -17 or k= -47

c) (x-6)^2 + (y-2)^2 = 20



2)
a) -i-3j

b) i) |v| = root(1+k^2)
u.v. = k-2

ii) k = 1/3 and k = -3

c) i) 1/2a + c
ii) c - 1/2a
iii) Got it a few times jus to be sure:P oc = cr, aq = qr yada yada yada
ocr is colinear....pretty sure i got that one but it seemed kinda easy for a C part



3)
a) a = 8

b) i) P= (-k/4, 0) Q = (0, k/5)
ii) k = plus r minus 20

c) i) (1-m)X - (1+m)Y -2c = 0
ii) m = 0, m=1, m=-1


Very unsure about 4 and 5....my weakest questions
4)
a) 30, 120

b) x = 0, 120, 240, 360.

c) i) break into the three dotted triangles, Area of each is 1/2(b)(r), 1/2(c)(r) and half(a)(r)...factorise out 1/2(R)

ii) started pythag but seemed too easy....messin around with trig for one page...attempt marks....kickin myself!

iii) r = q (p^2 - q^2) all over p + q


5) mostly proofs or showing....didnt get the C part out, got as far as Cos3x = (3^.5)Sin3x = 0 ???????????



8)
a)xLogx - x (omitted the + C :mad: )

b) i) area in p = 18p - 2p^3
ii) p = rt3, max area = 12rt3

c)
i) Cosx = 1 - x^2/2! + x^4/4! - x^6/6! + x^8/8! - x^10/10! etc etc
ii) Arsed around with a bit a trig...hoping for attempt marks
iii) wasnt sure atall atall....got 11/40 tho which seemed neat enough???


Cant wait till 18th August....dying to see what I got!!

Raped in Irish 2 tomorrow:(

foxpoint1

how many marks would i get for only evaluating one value for K in the circle??
damn absolute value sign!!
and what about the difference equation?i got it done as far as factorisng the alpha and betas when put into the equation..ran out of time.
apart from that im delighted with how it went.

EuropeanSon

psychoduck wrote: »

this paper was a disgrace for me, my brain simply didnt work at all
I couldnt do my favourite question, Q4 part c) at all! nothing worked out!
In 5c) ii I messed up the angles in the end, but the procedure was right
and Q8, oh dear... in part a) i integrated dx as 1 instead of x, my maths teacher said it would be only 3 points, but still...
and for the part b) i got the area 81, and i still dont know where i went wrong!

(i) the expression for the area was 18p-p^2, wasnt it?
(ii) so i differentiated it and got
18 - 2p = 0
p = 9
and then when put into the formulae for the area i got:
A = 162 - 81 = 81

Please, tell me, what I did wrong, because its killing me!
...do you think I can still get an A1 considering the paper 1 went smoothly enough?

Area was 18p-2p^3 I think.
Edit: yep, looked at it again, it was.

dynamot

Reillyman wrote: »

Anyone else get these answers?

1.(b)(ii) [latex] k=-17, k=-47[/latex]


4.(c)(iii) [latex] r=\frac{bc}{2a}[/latex]


5.(c)(ii) [latex] x= 10^{\circ}, 70^{\circ}, 130^{\circ}, 190^{\circ}, 250^{\circ}, 310^{\circ} [/latex]


6.(a) [latex] \frac{2}{7} [/latex]


8.(a) [latex] x\log_e x -x+c [/latex]

(b)(ii) [latex]12\sqrt3 [/latex]

(c)(ii) [latex]\frac{331}{1440} [/latex]

everything but the trig equation

KealanOCarroll

psychoduck wrote: »

this paper was a disgrace for me, my brain simply didnt work at all
I couldnt do my favourite question, Q4 part c) at all! nothing worked out!
In 5c) ii I messed up the angles in the end, but the procedure was right
and Q8, oh dear... in part a) i integrated dx as 1 instead of x, my maths teacher said it would be only 3 points, but still...
and for the part b) i got the area 81, and i still dont know where i went wrong!

(i) the expression for the area was 18p-p^2, wasnt it?
(ii) so i differentiated it and got
18 - 2p = 0
p = 9
and then when put into the formulae for the area i got:
A = 162 - 81 = 81

Please, tell me, what I did wrong, because its killing me!
...do you think I can still get an A1 considering the paper 1 went smoothly enough?

Graph is given by y = 9 - x^2.
Area of box is base by height. base is 2p, height is given by subbing p into the graph function in the place of x. Height is given by 9 - p^2...
area base x height....A = 2p ( 9 - p^2)
A = 18p - 2p^3.
differentiate it = 18 - 6p^2
solve dydx = 0 for a stat point. p = rt3
sub p = rt3 into d2y dx sqrd to prove its a max.
sub p = rt3 back into area function 18p - 2p^3 to get the max area = 12rt3

Ashashi

The trig question 5 was the easiest trig I have seen in a long time. q 4 can go jump off a bridge the bastard.

EuropeanSon

Ashashi wrote: »

The trig question 5 was the easiest trig I have seen in a long time. q 4 can go jump off a bridge the bastard.

Q4 was awkward, the only one I don't think I got full marks in. Couldn't get (c)(iii).

KealanOCarroll

Ashashi wrote: »

The trig question 5 was the easiest trig I have seen in a long time. q 4 can go jump off a bridge the bastard.

4 was sound apart from c ii and ciii....
q5 raped me:(

Making It Bad

I loved both the trig questions. 4c seemed daunting at first but wasn't bad when you got into it. Still didn't get the last part of the c though.

Cliodhna.

I reckon i passed ! and that'll do! ha.... Oh ya for the colinear in vectors could ya say if this is true: AR= AQ + QR then it is colinnear... rearrange and you get 0=0 ?

psychoduck

EuropeanSon wrote: »

Area was 18p-2p^3 I think.
Edit: yep, looked at it again, it was.

well, than its a mystery for me how the hell i got 18p-p^2.
I must have done 2p(9-p) = 18p-p^2; which means omitting the power 2 in the bracket and then even multiplied wrongly. omg. :eek: shoot me! :mad:
how many points would i lose for that do you think?

...and there are so many answers for Q2 b) ii, which one is correct? i got k = 1/2 and -3/2, but i'm quite sure i screwed something again

johndoe91

JerCotter7 wrote: »

Well if you showed that 2c = r then that is it proven. Just have to say it's collinear then.

k im not going to argue this anymore because i know where your coming from but 2c=r does not show its because as you already agreed with me....CB = A where they arent on the same line! all you had to show was that CR= C, that shows its on the same line.....

psychoduck

how did ye get 2/7 for 6a)?
I got 1/6, because 4/10 x 5/12

EuropeanSon

psychoduck wrote: »

well, than its a mystery for me how the hell i got 18p-p^2.
I must have done 2p(9-p) = 18p-p^2; which means omitting the power 2 in the bracket and then even multiplied wrongly. omg. :eek: shoot me! :mad:
how many points would i lose for that do you think?

...and there are so many answers for Q2 b) ii, which one is correct? i got k = 1/2 and -3/2, but i'm quite sure i screwed something again

I think I got 3 and -1/3, or maybe the signs were the other way round, I don't remember It was correct though, it satisfied everything. Hard to know how much you'd lose, but if you did (b)(ii) correctly using that figure you should get full marks on that, so maybe just a blunder or perhaps losing the 5 marks for (i)?
I'd expect a tough marking scheme, as most seemed to like the paper, so probably the latter.

foxpoint1

i got the same and its right for 6a. 1/6

what did ye get for 7b) part 3? i got 23/48

EuropeanSon

psychoduck wrote: »

how did ye get 2/7 for 6a)?
I got 1/6, because 4/10 x 5/20

5/20? You mean 5/12. 1/6 was correct though.

Pimptastic

For Q8ciii did you have to change sin 1/2 to radians? Coz otherwise it doesn't give you the right answer.

JerCotter7

johndoe91 wrote: »

k im not going to argue this anymore because i know where your coming from but 2c=r does not show its because as you already agreed with me....CB = A where they arent on the same line! all you had to show was that CR= C, that shows its on the same line.....

But AB = OC. Not the same line. So your way is just the exact same.

Also technically CB =/= A
|CB| = |A|

psychoduck

EuropeanSon wrote: »

5/20? You mean 5/12. 1/6 was correct though.

yes, 5/12. did i mention my brain gave up on me today?