Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie

biology question

  • 25-06-2010 9:06pm
    #1
    Registered Users Posts: 20


    Twenty five colonies grew in nutrient agar from 1.0 ml of sample withdrawn from a solution diluted to 10-5 in a standard plate count procedure. How many cells were in the original sample?

    Anyone no how to work this out?
    thanks!


Comments

  • Moderators, Recreation & Hobbies Moderators, Science, Health & Environment Moderators, Technology & Internet Moderators Posts: 92,367 Mod ✭✭✭✭Capt'n Midnight


    by 10-5 do you mean 10E-5 / 1 in 100,000 dilution ?


    No idea since the cells could be clumped :p
    but you could count the colony forming units by multiplying back the dilutions

    if there are 25 per ml then at the previous 1:10 dilution there were 250 per ml


  • Closed Accounts Posts: 2,980 ✭✭✭Kevster


    She must mean 10^-5? In that case, the answer would be 2,500,000 cells? If it was a 10^-5 dilution, that's 1-in-100,000. You just multiply this by 25 to get the answer I think.

    Kevin


  • Moderators, Regional East Moderators Posts: 23,225 Mod ✭✭✭✭GLaDOS


    Kevster wrote: »
    She must mean 10^-5? In that case, the answer would be 2,500,000 cells? If it was a 10^-5 dilution, that's 1-in-100,000. You just multiply this by 25 to get the answer I think.

    Kevin
    Yeah, it's 25 x 10^5 = 2,500,000. However that's not cells, it's colony forming units per ml (cfu/ml) as Capt'n said.

    Cake, and grief counseling, will be available at the conclusion of the test



Advertisement