hex values c++ ...

the_monkey

Eh, this is mad .. but i am using hex numbers in a c++ program
yet they are being treated like decimal numbers, so i did a simple test :

int main()
{
 
    int x = 0x9;
    int y = 0x7;
    int z = x+y;
    cout <<z;

    return 0;
}
 

I am getting 16 as the value of z, rather then 0x10 ,

do i need more then the 0x to state that it is in hex ?

ressem

it doesn't matter whether you enter
int x = 0x0F;
or
int x = 15
you are just setting x to 00000000...00001111 binary

The base that you used originally isn't stored.
What you are looking to do is set the output format to hex to display the binary number using a different base than the default which is decimal.

this can be done by
std::cout<<std::hex<<z

or
cout<<hex<<z
when you are using namespace std

http://www.cplusplus.com/reference/iostream/manipulators/hex/

and if you want to display the 0x prefix then you use
cout<<hex<<showbase<<z