Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie

* Honours Maths Paper 2 " Let's fight back :)

Options
1457910

Comments

  • Closed Accounts Posts: 2 aoifegibney


    well this thread is making me feel horrendously unprepared...


  • Closed Accounts Posts: 35 epicwinning


    Was flicking through an old copy and came across an easy way to do the MacClauren Series for tan-1(x) if anyone else finds that one annoying:

    First, differentiate tan-1(x):

    d/dx(tan-1(x)) = 1/(1+x^2)

    Then use long division to get a few terms for the RHS:

    mcle.pngmcl.png?action=view&current=mcl.pngmcl.th.png

    Then integrate both sides:

    tan-1(x) = INT[(1) - (x^2) + (x^4) ...]
    tan-1(x) = x - (x^3)/3 + (x^5)/5 ...


    It's a much easier way of doing that series.


  • Registered Users Posts: 140 ✭✭MikeHough


    You are correct.

    thank you. I thought so.:p

    o.d. morris should be ashamed of himself.:pac:


  • Registered Users Posts: 140 ✭✭MikeHough


    Was flicking through an old copy and came across an easy way to do the MacClauren Series for tan-1(x) if anyone else finds that one annoying:

    First, differentiate tan-1(x):

    d/dx(tan-1(x)) = 1/(1+x^2)

    Then use long division to get a few terms for the RHS:

    mcle.pngmcl.png?action=view&current=mcl.pngmcl.th.png

    Then integrate both sides:

    tan-1(x) = INT[(1) - (x^2) + (x^4) ...]
    tan-1(x) = x - (x^3)/3 + (x^5)/5 ...


    It's a much easier way of doing that series.


    that's the same way as the texts and tests....page 241


  • Closed Accounts Posts: 35 epicwinning


    Don't have Texts and Tests. We just did it the same way as all the others :P


  • Advertisement
  • Registered Users Posts: 86 ✭✭xxpopopxx


    Can anyone please help me out?? For the MacLaurin series how do you get the general term of a series? My teacher only thought us the basics and nothing deeper, I'm freaking out and I keep crying :(


  • Closed Accounts Posts: 29 hairybacon




  • Registered Users Posts: 281 ✭✭NSNO


    For 2007 Q3 (c) (i), would it be correct to state that the given is a line and intersect the two lines and sub the points into the given equation to prove its on the intersection?

    You'd get K(0) + L(0) which = 0 as per given, therefore proven it's on the intersection? Because I'm not quite getting the second part of the given answer on the marking scheme. (http://examinations.ie/archive/markingschemes/2007/LC003ALPO00EV.pdf)


  • Registered Users Posts: 32 joyle


    If the SEC want to show how great project maths is by throwing graphs at us, I believe we should brush up on trig graphs and Q8 graph questions too!!


  • Registered Users Posts: 10,992 ✭✭✭✭partyatmygaff


    joyle wrote: »
    If the SEC want to show how great project maths is by throwing graphs at us, I believe we should brush up on trig graphs and Q8 graph questions too!!
    Wouldn't it be sweet if they asked us just to draw the graphs of all the trig functions...


  • Advertisement
  • Registered Users Posts: 47 dannyirishman


    Having a relapse... What is after (N+1)!

    Is it (N+1)N!..........(N-1)!


  • Registered Users Posts: 281 ✭✭NSNO


    Wouldn't it be sweet if they asked us just to draw the graphs of all the trig functions...

    I'd love the 2009 question. Any question which is answerable with "Sin-1(x) is bijective" is a good question. :D


  • Registered Users Posts: 135 ✭✭hunii07


    Having a relapse... What is after (N+1)!

    Is it (N+1)N!..........(N-1)!


    It's (N+1)N!


  • Registered Users Posts: 281 ✭✭NSNO


    Having a relapse... What is after (N+1)!

    Is it (N+1)N!..........(N-1)!

    (N+1)! = (N+1)N! = (N+1)(N)(N-1)! = (N+1)(N)(N-1)(N-2)!......


  • Registered Users Posts: 32 joyle


    Wouldn't it be sweet if they asked us just to draw the graphs of all the trig functions...

    or they do like what they did in 06 and 09! would love it


  • Closed Accounts Posts: 494 ✭✭PJelly


    Question about getting the general term... say you have the series 1+X+X^2/2!+X^3/3! etc. Do you read 1 as the first term or X as the first term?
    And if there's no 1 (as in Ln(1+x)) do you read the X as the first term?
    My teacher once mentioned something about reading something as the 0'th term, which I thought made no sense.


  • Closed Accounts Posts: 35 epicwinning


    xxpopopxx wrote: »
    Can anyone please help me out?? For the MacLaurin series how do you get the general term of a series? My teacher only thought us the basics and nothing deeper, I'm freaking out and I keep crying :(


    Step 1: Sign
    If there all positive, the U(n) is positive, same with negative.
    If it alternates, stick a (-1)^n or (-1)^(n+1) before the gen term.

    Step 2: Pattern of x
    Find a pattern for the x powers
    eg. x, x^2, x^3 add x^n
    x, x^3, x^5 add x^(2n-1)

    Step 3: Denominator

    There should be a similar pattern for the denominator

    Step 4: Check with 2 random terms.


  • Registered Users Posts: 32 joyle


    PJelly wrote: »
    Question about getting the general term... say you have the series 1+X+X^2/2!+X^3/3! etc. Do you read 1 as the first term or X as the first term?
    And if there's no 1 (as in Ln(1+x)) do you read the X as the first term?
    My teacher once mentioned something about reading something as the 0'th term, which I thought made no sense.

    what ever is the 1st term, read it as the 1st term, whether it be 1 or x


  • Closed Accounts Posts: 35 epicwinning


    PJelly wrote: »
    Question about getting the general term... say you have the series 1+X+X^2/2!+X^3/3! etc. Do you read 1 as the first term or X as the first term?
    And if there's no 1 (as in Ln(1+x)) do you read the X as the first term?
    My teacher once mentioned something about reading something as the 0'th term, which I thought made no sense.

    You could do either to be honest... I'd say let 1 be the first term.

    U(n) = [x^(n-1)]/(n-1)!


  • Closed Accounts Posts: 494 ✭✭PJelly


    Thanks :)
    My teacher used to say something about not reading one as a term... made no sense to me.
    I just got 2005 8 all right too! Progress!
    Hopefully things go as smoothly on the day.


  • Advertisement
  • Registered Users Posts: 86 ✭✭xxpopopxx


    Step 1: Sign
    If there all positive, the U(n) is positive, same with negative.
    If it alternates, stick a (-1)^n or (-1)^(n+1) before the gen term.

    Step 2: Pattern of x
    Find a pattern for the x powers
    eg. x, x^2, x^3 add x^n
    x, x^3, x^5 add x^(2n-1)

    Step 3: Denominator

    There should be a similar pattern for the denominator

    Step 4: Check with 2 random terms.

    thank you so much! ill try that


  • Registered Users Posts: 57 ✭✭conlufc


    Having a relapse... What is after (N+1)!

    Is it (N+1)N!..........(N-1)!

    ye your right


  • Closed Accounts Posts: 494 ✭✭PJelly


    NSNO wrote: »
    (N+1)! = (N+1)N! = (N+1)(N)(N-1)! = (N+1)(N)(N-1)(N-2)!......
    I just remember that you keep taking off one. And when you want to stop place a factorial (!) on the last one you do.


  • Closed Accounts Posts: 494 ✭✭PJelly


    That awkward moment when you manage to spill your tea on every single maths book you own at the same time.


  • Registered Users Posts: 334 ✭✭B_Fanatic


    You could do either to be honest... I'd say let 1 be the first term.

    U(n) = [x^(n-1)]/(n-1)!

    Is that denominator right? I mean if the first term is one wouldn't n - 1 make it infinity? Or do I just disregard it because factorial doesn't go as far as zero? E.g. 4! =/= 4x3x2x1x0 :rolleyes:


  • Registered Users Posts: 35 easkey92


    what are all d properties for standard deviation and means ?? please help :(


  • Registered Users Posts: 46 jamesr1775


    PJelly wrote: »
    That awkward moment when you manage to spill your tea on every single maths book you own at the same time.
    lol pwned!! ahhh well last few hours of using them is left anyway


  • Registered Users Posts: 343 ✭✭Digits


    B_Fanatic wrote: »
    Is that denominator right? I mean if the first term is one wouldn't n - 1 make it infinity? Or do I just disregard it because factorial doesn't go as far as zero? E.g. 4! =/= 4x3x2x1x0 :rolleyes:

    0! = 1

    ;)


  • Closed Accounts Posts: 494 ✭✭PJelly


    jamesr1775 wrote: »
    lol pwned!! ahhh well last few hours of using them is left anyway

    My papers are literally stuck to the table :p


  • Advertisement
  • Closed Accounts Posts: 494 ✭✭PJelly


    Digits wrote: »
    0! = 1

    ;)

    I love scaring the ordinary maths lads by putting 9/0! on the calculator and showing how it equals nine. It's my party trick.


This discussion has been closed.
Advertisement