** Higher Level Maths Paper 1 2012 Before/After **

Hermione Granger

Epsi wrote: »

Yes. I thought it was a mistake at first , but I kept looking through my answer and it seemed to fit.

Same here how did you show that there was no term independent of x ?
How did you guys in q2c show that f(x)in increasing was it just a positive value for the slope did
get a chance to finish it off properly

Maybe_Memories

Paper still not up.

leaveiton

WestIRL wrote: »

Hahahha yeah I was exactly the same. OH SWEET INTEGRATION AREA QUESTION!!

(2min later)

....oh dear GOD!

It was awful, cause I could get b (ii) out so I said to myself "Oh well, at least I have this lovely part C," then I read it

liamduffy1994

rkeano5 wrote: »

No.. I got something fairly regular, 210 perhaps?

210 was the 10C4 answer but when the powers were brought to the coefficients it gave a strange answer due to the fraction

RedTexan

For 8 (c) (ii) 2k by the square root of k over 3

Mista

K_1 wrote: »

210 was right for 10C4, but the rest doesn't cancel out to i think you have to include it. I hope!!!

I got 210 by 6x to the power of 8? Final answer was 1260

WestIRL

ChemHickey wrote: »

To be honest, it feel sorry for those who's teachers hadn't covered 4 or 5. They were by far the easiest questions on the paper!

Cosmic.Postman

liamduffy1994 wrote: »

Did anybody else get 9658.125 as there coefficient to to x in 5C(ii)?

Yeah boiii!

Wesc.

ChemHickey wrote: »

To be honest, it feel sorry for those who's teachers hadn't covered 4 or 5. They were by far the easiest questions on the paper!

I agree, got Q4 done in under 10 minutes :P


How did you do 5 (c) (i) ? It was driving me crazy in the exam.

liamduffy1994

RedTexan wrote: »

For 8 (c) (ii) 2k by the square root of k over 3

I got k and root k, root k seems to be the correct answer! I subbed k as my a value at the end though so double mistake there!

Dazaq

some thing similar if i remember correctly

DepoProvera

Hermione Granger wrote: »

Same here how did you show that there was no term independent of x ?

I said that 20 -3r=0 ----> r=20/3 which is invalid as you can't chose from 10 with that r.. A proof by contradiction? :P

rkeano5

K_1 wrote: »

210 was right for 10C4, but the rest doesn't cancel out to i think you have to include it. I hope!!!

oh drat, you're right (unfortunately):)

Wesc.

RedTexan wrote: »

For 8 (c) (ii) 2k by the square root of k over 3

Yeah I got the same! Integration was such a nice question.



For 7 (c) (iii) were ye guys getting 0.75 then 0.5 then 0.75 then 0.5.......etc.?

Epsi

Hermione Granger wrote: »

Same here how did you show that there was no term independent of x ?

x^0 for term independent of x , so I let x^20-3r = x^0
Got 20 over 3 equal to r. Which was 6.666 recurring so I said there is no term independent of X as you can't have 0.6666 of a term. what I did anyways.

RedTexan

liamduffy1994 wrote: »

I got k and root k, root k seems to be the correct answer! I subbed k as my a value at the end though so double mistake there!

I got root k for my expression for a in terms of k if that's relevant?

DepoProvera

Epsi wrote: »

x^0 for term independent of x , so I let x^20-3r = x^0
Got 20 over 3 equal to r. Which was 6.666 recurring so I said there is no term independent of X as you can't have 0.6666 of a term. what I did anyways.

I said this too.

leaveiton

Wesc. wrote: »

For 7 (c) (iii) were ye guys getting 0.75 then 0.5 then 0.75 then 0.5.......etc.?

Yep!

BrianC2095

Did anyone do Q5 seq + series?

RedTexan

For question 3 (c) part 2 k=1?

GarIT

Is it ok to post scans of the paper? Or should I just wait until its online?

Wanchor

In terms of cos(2x)? I mean, in the heat of the exam how does begin to understand that.

TheBody

GarIT wrote: »

Is it ok to post scans of the paper? Or should I just wait until its online?

Post up scans please!!

BrianC2095

How did you do it? sub answer z^2 +k into the line?

mcpaddington

GarIT wrote: »

Is it ok to post scans of the paper? Or should I just wait until its online?

It's fine to post scans if you want.

DepoProvera

BrianC2095 wrote: »

Did anyone do Q5 seq + series?

Yeah I did. a) grand b) normal telescoping c) tough but I got b^2=ac then did the standard thing for consec arithmetic terms and it worked out to b^2=ac which had been proved true from earlier

Jan_Itor

For 1b(ii) it said you had to find to find cubic equation where the roots were 1 less than the roots of f. I just did f(x-1) worked it out and got a cubic equation is that right?

Hermione Granger

Q 5 b ii
10 ncr 4multiply by 3x to the power of six multiply by 1 over 2x to the power og 4 is

210 x 729 x .0625 =
9568.125

Wesc.

RedTexan wrote: »

For question 3 (c) part 2 k=1?

Yes Yes Yes! I got the out in the last minute haha.


Guys I'm actually in dreamland now I think it's a 100%!

Dapics

Wanchor wrote: »

In terms of cos(2x)? I mean, in the heat of the exam how does begin to understand that.

Its a trick question!

All you had to do was divide by two a few times and then let the equation =0 an bring across cos2x...

Beautiful Beautiful paper.... Im so happy.

8) C, was impossible
1) B almost caught me out, the shnakes asking for an integer! I only just managed to remember what an integer was and figured out it was a trick question