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** Higher Level Maths Paper 1 2012 Before/After **

12467…18

Comments

  • #92
    Owen_S
    Registered Users Posts: 1,211 ✭✭✭Owen_S


    DepoProvera wrote: »
    Don't know if this cleared anything up for you...

    <picture>
    Dafuq is that?


  • #93
    mcpaddington
    Closed Accounts Posts: 358 ✭✭mcpaddington


    As long as you attempt every single question you'll be grand!


  • #94
    finality
    Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    leaveiton wrote: »
    Guys, don't stress about the discs/circles, look at page 88 of this PDF of the syllabus, they can only ask cones and spheres! http://www.ncca.ie/en/Curriculum_and_Assessment/Post-Primary_Education/Project_Maths/Syllabuses_and_Assessment/LC_Maths_for_examination_in_2012.pdf

    No no no, deriving the formula of the area of a circle CAN come up, that was only referring to volumes! However, it's extremely unlikely considering it came up last year.


  • #95
    leaveiton
    Closed Accounts Posts: 1,778 ✭✭✭leaveiton


    finality wrote: »
    No no no, deriving the formula of the area of a circle CAN come up, that was only referring to volumes! However, it's extremely unlikely considering it came up last year.

    Oh, okay, sorry then! :o Just got a wee bit excited.


  • #96
    DepoProvera
    Registered Users, Registered Users 2 Posts: 404 ✭✭DepoProvera


    Owen_S wrote: »
    Dafuq is that?

    Erm 2003 Q3cii someone asked for.. or you can't read my godawful scribbles? :(

    (sorry for the large picture btw)


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  • #97
    Saracarroll
    Registered Users Posts: 64 ✭✭Saracarroll


    DepoProvera wrote: »
    You can only be asked to rotate lines or spheres about either the x or y axis.(aswell as the standard area beneath curve/between two curves)

    They are volumes, i was wondering about area. I think it can only be a circle.....


  • #98
    Mark1724
    Registered Users Posts: 13 ✭Mark1724


    so 38% overall is a d3 definitely?


  • #99
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    Right O everyone.... Be prepared to answer questions that are as hard as last years.... there going to test you knowledge behind what there asking you.... How Do I know?

    I dont.... but I'm just saying, there not going to lower the standard, there gonna keep it at last year's level.


  • #100
    DepoProvera
    Registered Users, Registered Users 2 Posts: 404 ✭✭DepoProvera


    Saracarroll wrote: »
    They are volumes, i was wondering about area. I think it can only be a circle.....

    Well then you're just talking about normal integration of a curve to the x and y axis then? (circle=curve)


  • #101
    finality
    Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    leaveiton wrote: »
    Oh, okay, sorry then! :o Just got a wee bit excited.

    Sorry, reading back over my post I sounded really angry, didn't mean to :L


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  • #102
    leaveiton
    Closed Accounts Posts: 1,778 ✭✭✭leaveiton


    finality wrote: »
    Sorry, reading back over my post I sounded really angry, didn't mean to :L

    Oh no, you didn't sound angry at all! Don't worry! :)

    Ah god I'm really scared for tomorrow :( Going to get up quite early to study I think, I don't do geography so I have the whole morning.


  • #103
    lemonz
    Registered Users Posts: 13 ✭lemonz


    Quick question, there seems to be two proofs of De Moivre's Theorem, one where n E Z and the second by induction. If avoiding Q 4 and 5, is there any need to learn it by induction?


  • #104
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    DepoProvera wrote: »
    Well then you're just talking about normal integration of a curve to the x and y axis then? (circle=curve)


    No the circle is not the curve... that defies logic.

    The integration of the curve is the point where y=0, i.e where the curve hits the x-axis... you use these x-values and sub them in to the integral of the curve equation, then you have area under the curves area.

    This is unless the curve doesn't touch the x-axis in which case, a tangent/line will be given. You then let the line=tangent and find x-values, bring them down to the x-axis and then you have your x-values... if the curve is above the x-axis and there is a tangent that cuts an area so that the area of the curve is under the curve and under the line, then remember you must also find the area of the square/rectangle underneath the curve and subtract the area of the curve from it.

    Hope this helps.... circles do not come into integration, At least I dont think so.

    There may be a proof, i think there is to find using integration the area of a circle but i wouldn't go near that question.


  • #105
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    lemonz wrote: »
    Quick question, there seems to be two proofs of De Moivre's Theorem, one where n E Z and the second by induction. If avoiding Q 4 and 5, is there any need to learn it by induction?

    Learn the general equation proof.... it is a favourite to appear on the paper... also watch out for factor theorem, it could be the dark horse of the paper.


  • #106
    Theorems
    Registered Users Posts: 14 ✭Theorems


    I'm screwed for maths, don't know how I managed to stay higher for the leaving..
    5 hours study tomorrow morning should hopefully get me a pass

    Hopefully...


  • #107
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    Theorems wrote: »
    I'm screwed for maths, don't know how I managed to stay higher for the leaving..
    5 hours study tomorrow morning should hopefully get me a pass

    Hopefully...

    Be warned... this paper will be as hard as last years.


  • #108
    Saracarroll
    Registered Users Posts: 64 ✭✭Saracarroll


    DepoProvera wrote: »
    Well then you're just talking about normal integration of a curve to the x and y axis then? (circle=curve)


    No its not, but thanks


  • #109
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    Saracarroll wrote: »
    No its not, but thanks

    I've answered your question, see previous page.


  • #110
    Wanchor
    Registered Users Posts: 114 ✭✭Wanchor


    I hate the way everything is so modular. If its not on the course, I don't want to learn it seems to be the approach with everything on the leaving cert and that saddens me. I want to learn! I like knowledge!


  • #111
    DepoProvera
    Registered Users, Registered Users 2 Posts: 404 ✭✭DepoProvera


    Look at the 2011. You're integrating y=/r^2 - x^2/ with limits 0 to r.. Which is a quarter of a circle which is a curve, no?


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  • #112
    Saracarroll
    Registered Users Posts: 64 ✭✭Saracarroll


    Dapics wrote: »
    I've answered your question, see previous page.


    Thanks, i thought it was just the circle, just checking :)


  • #113
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    DepoProvera wrote: »
    Look at the 2011. You're integrating y=/r^2 - x^2/ with limits 0 to r.. Which is a quarter of a circle which is a curve, no?

    In that case and in that light then yes perhaps.

    Good observation

    I better get studying integration again!


  • #114
    finality
    Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    Dapics wrote: »
    No the circle is not the curve... that defies logic.

    The integration of the curve is the point where y=0, i.e where the curve hits the x-axis... you use these x-values and sub them in to the integral of the curve equation, then you have area under the curves area.

    This is unless the curve doesn't touch the x-axis in which case, a tangent/line will be given. You then let the line=tangent and find x-values, bring them down to the x-axis and then you have your x-values... if the curve is above the x-axis and there is a tangent that cuts an area so that the area of the curve is under the curve and under the line, then remember you must also find the area of the square/rectangle underneath the curve and subtract the area of the curve from it.

    Hope this helps.... circles do not come into integration, At least I dont think so.

    There may be a proof, i think there is to find using integration the area of a circle but i wouldn't go near that question.

    Circles do come into integration, have you not seen last year's paper?


  • #115
    Dapics
    Registered Users Posts: 568 ✭✭✭Dapics


    finality wrote: »
    Circles do come into integration, have you not seen last year's paper?

    Alas the area of a disc.... ok ok...my bad.


  • #116
    Incompetent
    Registered Users Posts: 442 ✭✭Incompetent


    DepoProvera wrote: »
    Don't know if this cleared anything up for you...


    THANK YOU! It was actually really simple. I'm just completely out of it!

    You've earned my life long love; aren't you lucky :p


  • #117
    ei.sderob
    Closed Accounts Posts: 108 ✭✭ei.sderob


    I've got this awful feeling that it's gonna be one of those years, just horribly difficult like.


  • #118
    leaveiton
    Closed Accounts Posts: 1,778 ✭✭✭leaveiton


    Okay, quick complex number question!

    I don't entirely understand how you get the argument when you convert a number to polar form. I know that when it's in quadrant 1, you just use the angle. And for quadrant 2, you just get the angle and take it away from pi/2.

    However, I really really don't understand when it's in the 3rd or 4th quadrant! Does anyone have a quick explanation or know of anywhere that would explain it to me? :o


  • #119
    finality
    Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    leaveiton wrote: »
    Okay, quick complex number question!

    I don't entirely understand how you get the argument when you convert a number to polar form. I know that when it's in quadrant 1, you just use the angle. And for quadrant 2, you just get the angle and take it away from pi/2.

    However, I really really don't understand when it's in the 3rd or 4th quadrant! Does anyone have a quick explanation or know of anywhere that would explain it to me? :o

    My radians aren't the best, but wouldn't you take it away from pi, not pi/2?


  • #120
    leaveiton
    Closed Accounts Posts: 1,778 ✭✭✭leaveiton


    finality wrote: »
    My radians aren't the best, but wouldn't you take it away from pi, not pi/2?

    Yes, you would, apologies! I do know that, I swear... :P


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  • #121
    ChemHickey
    Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    finality wrote: »
    My radians aren't the best, but wouldn't you take it away from pi, not pi/2?

    Finality is right

    To get the argument. Get the tan of the angle as normal. Then, if it is in the third quadrant, treat it as like it was in the first quadrant, but add the angle to -pi. In the fourth quadrant, you take the angle you get and change the sign,

    I hope this makes sense, I don;t do it this way but i think it may make a bit of sense.


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