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Chemistry Question

  • 16-06-2012 10:41am
    #1
    amy-marie
    Registered Users Posts: 34 ✭


    I'm trying to do the 2003 question on volatile liquids (Q3) and I'm totally lost on the calculation. So far I've got this:

    P1 V1 = P2 V2
    T1 T2

    1 x 10 (to the power of 5) x 95 =
    370

    But I have no idea what I'm doing. Any of you chemistry geniuses wanna explain it to me?


Comments

  • #2
    SuchGold
    Registered Users Posts: 14 ✭SuchGold


    Use the PV=nRT formula. Change the volume to from cm to metres cubed so you multiply it by 10^-6. Temperature needs to be in kelvin so add on 273.
    Then find n which is the number of moles. Then use the grams = moles x molar mass formula to find the molar mass. (grams is .275)


  • #3
    amy-marie
    Registered Users Posts: 34 ✭amy-marie


    Oh, that is so much easier! Thank you so much, I got it to work out :D


  • #4
    Random_Person
    Registered Users Posts: 328 ✭✭Random_Person


    SuchGold wrote: »
    Use the PV=nRT formula. Change the volume to from cm to metres cubed so you multiply it by 10^-6. Temperature needs to be in kelvin so add on 273.
    Then find n which is the number of moles. Then use the grams = moles x molar mass formula to find the molar mass. (grams is .275)

    Just an FYI but there's an even easier way of changing cm3 into m3.

    Just take any value in cm3 and divide it by 1,000,000. Finding this out made these questions sooo much easier.


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