Php Question

Devi

Hi all

Doing php in college and have been asked to create a coin toss program whereyou win if you get two heads in a row. Thought I had it, but I keep getting the"Undefined offset: 0 on line 16" error which seems to mean that that$check is getting decremented even when $i is not greater than two, which meansthe ‘if’ is getting ignored, but why?

Sorry if this a real basic question, only started programming, still trying to get my head around the logic, have to say I’m am loving itthough.


[php]
<?php
$tosses = array();
$numTosses = 4;
for($i = 1;$i <= $numTosses; $i++) {
$coin = rand(0,1);
if ($coin == 0)
{
$tosses[$i] = "Heads";
if ($i >= 2); //seems to be ignored
{
$check = $i - 1;
if($tosses[$check] == "Heads")
{
echo "You got two heads in a row, you won";
exit();
}
}
}

else {
$tosses[$i] = "Tails";
}

}
echo "Sorry didnt win this time";

?>

[/php]

Sparks

Devi wrote: »

[php]
if ($i >= 2); //seems to be ignored
[/php]

It's the semicolon. Remove it...

Devi

Sparks wrote: »

It's the semicolon. Remove it...

oh dear lord, how did I not see that. Thanks Sparks.