Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie

** HL Physics Before / after **

11315171819

Comments

  • Registered Users, Registered Users 2 Posts: 1,026 ✭✭✭Leaving Cert Student


    God I dont know why I come on here thought I had A1 in the bag now realize I got at least 2 q5's wrong and last bit of q6...


  • Registered Users Posts: 166 ✭✭xJEx


    It wouldn't have been a straight line the whole way. The book specifies that it is only within this limit that it is directly proportional. As you increase the Current there will be a heating effect, causing the resistance to rise as well. This explains why the graph started to curve slightly toward the higher values for the voltage.

    What do you mean? In the book, it's a straight line the whole way. My graph looked the same, as expected.


  • Registered Users Posts: 3 Cdawg95


    Jackobyte wrote: »
    Pretty much the same. My mass of the earth came out as 5.95x10^22, but I had carried all nine decimal places of ω up to that point which may have accounted for the difference.

    I got 6.5x10^24.... Mass of earth is usually to power of 24 too!


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    12 a 8-8cos30 m, 4.58 m/s, i got a = 2000ish and then F = 12585.84N?


  • Registered Users, Registered Users 2 Posts: 1,115 ✭✭✭magicianz


    The line is curved in real life. iirc from my own leaving cert, they do want the line to curve off for the upper ranges due to the increased resistance from the heating effect.


  • Advertisement
  • Registered Users Posts: 149 ✭✭D_s


    Cdawg95 wrote: »
    I got 6.5x10^24.... Mass of earth is usually to power of 24 too!

    Thank god you were the same, these other answers were scaring me! Yeah I got about that also :)


  • Registered Users, Registered Users 2 Posts: 6,321 ✭✭✭Jackobyte


    Cdawg95 wrote: »
    I got 6.5x10^24.... Mass of earth is usually to power of 24 too!

    Sorry, meant to say 5.95x10^24. It was definitely to the power of 24.
    I added a line saying M=~6x10^24 after as well cause that is the value usually given in papers.


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    Jackobyte wrote: »
    Sorry, meant to say 5.95x10^24. It was definitely to the power of 24.
    I added a line saying M=~6x10^24 after as well cause that is the value usually given in papers.

    Mine was to the power of 24 as well, 22 was a typo.


  • Registered Users Posts: 166 ✭✭xJEx


    12 (b) max image 5th?


  • Registered Users, Registered Users 2 Posts: 6,321 ✭✭✭Jackobyte


    decisions wrote: »
    Mine was to the power of 24 as well, 22 was a typo.

    A typo I copied! :pac:


  • Advertisement
  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    Jackobyte wrote: »
    A typo I copied! :pac:

    :P


  • Registered Users Posts: 3 Cdawg95


    Jackobyte wrote: »
    Sorry, meant to say 5.95x10^24. It was definitely to the power of 24.
    I added a line saying M=~6x10^24 after as well cause that is the value usually given in papers.

    What formulae did you use for g? I used F=gm then subbed F value into F=Gmm/d^2


  • Registered Users, Registered Users 2 Posts: 6,321 ✭✭✭Jackobyte


    Cdawg95 wrote: »
    What formulae did you use for g? I used F=gm then subbed F value into F=Gmm/d^2

    The value of g at that height will be lower than 9.8, I used centripetal force, F=mrw^2 and let the resulting answer equal Newton's gravitational formula. Think that is right anyway. Will run through the calculations again now.

    Edit: Just checked it again, and got the same answer, ie. 5.95x10^24. I even tried it using F=mg using the gravity value provided in part IV, and still came out the same.


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    8 a) did anyone get .2816J?
    b) .033 ohms and how do you do (ii)?


  • Registered Users, Registered Users 2 Posts: 1,026 ✭✭✭Leaving Cert Student


    xJEx wrote: »
    12 (b) max image 5th?

    Did you have to multiply by 2 and add 1?


  • Registered Users Posts: 166 ✭✭xJEx


    Did you have to multiply by 2 and add 1?

    I did do that at first but i rubbed it out when I reread it - it said the highest order image not the maximum number of images


  • Closed Accounts Posts: 124 ✭✭maughantourig


    decisions wrote: »
    8 a) did anyone get .2816J?
    b) .033 ohms and how do you do (ii)?

    E=R(I^2)t

    E=(.33)(250^2)(10*60)=(big ass number)J


  • Registered Users, Registered Users 2 Posts: 1,160 ✭✭✭Eurovisionmad


    decisions wrote: »
    8 a) did anyone get .2816J?
    b) .033 ohms and how do you do (ii)?

    P=I^2R you sub in the given value for I and your answer for R you then get an answer in Watts which is J s^-1 so for a minute you multiply your answer by 60, is what I did anyway!


  • Registered Users Posts: 166 ✭✭xJEx


    anyone get 7.33x10^-10 for decay constant in 9? and 6.82x10^12 for N?


  • Registered Users Posts: 15 dave2610


    xJEx wrote: »
    anyone get 7.33x10^-10 for decay constant in 9? and 6.82x10^12 for N?

    Pretty sure that's exactly what I got.


  • Advertisement
  • Registered Users, Registered Users 2 Posts: 11,553 ✭✭✭✭Copper_pipe


    What did ye get for the focal length in q3


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    What did ye get for the focal length in q3

    17.something?


  • Registered Users, Registered Users 2 Posts: 59 ✭✭Kingkumar


    What did ye get for the focal length in q3

    17.9 i think (rounded up to .9 it was like .89 something)
    Cdawg95 wrote: »
    I got 6.5x10^24.... Mass of earth is usually to power of 24 too!
    i got 5.95x10^24. umm what do you guys think will be acceptable range?

    EDIT: NOOOOOOO i might have not remembered to include kg as the units :(


  • Registered Users Posts: 15 dave2610


    What did ye get for the focal length in q3

    .179m I think


  • Closed Accounts Posts: 301 ✭✭amicus


    that was by far the easiest physics exam ever I think :P YE 8.b was 0.33 ohms resistance..current 250 so 250squared by 0.33 by 10 by 60..


  • Closed Accounts Posts: 301 ✭✭amicus


    D_s wrote: »
    Thank god you were the same, these other answers were scaring me! Yeah I got about that also :)
    I got 5.9 ten power of 24..its the exact mass of earth in fact


  • Registered Users Posts: 64 ✭✭no scope codgod


    Kingkumar wrote: »
    17.9 i think (rounded up to .9 it was like .89 something)


    i got 5.95x10^24. umm what do you guys think will be acceptable range?

    The actual mass of the Earth is 5.97x10^24 so I'd say you're likely within the range


  • Closed Accounts Posts: 8,207 ✭✭✭decisions


    17.89cm sounds farmiliar.

    I got the last part of 8 correct :D


  • Closed Accounts Posts: 301 ✭✭amicus


    121 for tension ?


  • Advertisement
  • Registered Users Posts: 24 lisheen2308


    amicus wrote: »
    121 for tension ?

    198N


Advertisement