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****Leaving Certificate: Higher Level Maths Discussion****

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  • Registered Users Posts: 192 ✭✭Isitthough?


    Nimrod 7 wrote: »
    (10, 5) and (38, 5) I think.

    how did you get that? I said y=5 and then they gave you f(x) so I let them equal to see where they intersect used -b but I got weird values..Did I do it right or what?
    Aspiring wrote: »
    If you have the DEB mock on hand see Question 6A. That's exactly how Theorem 13 would come up I'd say.

    Yeah I know saw that that's fine but in 2013 2012 etc.. there different so I was just wondering if they changed them or something?


  • Registered Users Posts: 24 LC.student2014


    Do we have to know corollaries? I'm confused about all the things we have to know and know how to prove! :S


  • Registered Users Posts: 75 ✭✭jellytots95


    If you're asked to prove the sine rule, do you have to prove it both ways, with a triangle with an acute angle and with a triangle with an obtuse angle?


  • Registered Users Posts: 164 ✭✭Tesco TripleChicken


    Nimrod 7 wrote: »
    You don't even have to do any work for it tbh :confused:

    Wasn't y just 100-23?

    And A was just looking at the equation and realising y =A.


    Yeah, that's the one.

    I think the corollary is just the angles on the same arc bit.

    Yeah I did 100-23 and got Y, then I was messing around with it and thought, "no actually A is 73 not Y" and I just got confused I didn't think theyd be the same. Didnt do the rest of the Q anyway so doesnt really matter now

    Are one of the 3 theorems guaranteed to come up on Q6? Is there anything else that always comes up? Really need to do decent on P2 to pass maths


  • Registered Users Posts: 5 Maths Help Needed


    Can somebody help me please, what are the 3 theorems everyone is talking about ?
    Thanks in advance!


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  • Registered Users Posts: 17 Worried247


    I know this is random but does anyone know, if the reqirements for your college course are:
    OC3 or HD3 Mathematics and HC3 French
    and you fail higher level maths and think you defo would have gotten above an Ordinary c3, is there any way you can like take an exam or an OL exam during summer to get into the course in September without having to repeat your leaving or repeat maths for the year?


  • Registered Users Posts: 4 Rbrtmry


    There's a website that shows you how to do all of the costructions step by step if anyone wants. Just type "Leaving cert geometry constructions" into google and it comes up. I'd post a link but i'm not allowed do that for some reason.


  • Registered Users Posts: 274 ✭✭2thousand14


    how did you get that? I said y=5 and then they gave you f(x) so I let them equal to see where they intersect used -b but I got weird values..Did I do it right or what?

    Yes thats how I did it


  • Registered Users Posts: 82 ✭✭TooMuchStudy


    how did you get that? I said y=5 and then they gave you f(x) so I let them equal to see where they intersect used -b but I got weird values..Did I do it right or what?

    Yeah, you should've gotten numbers to decimals but it says round to the nearest number


  • Registered Users Posts: 10 hanza123


    Rbrtmry wrote: »
    There's a website that shows you how to do all of the costructions step by step if anyone wants. Just type "Leaving cert geometry constructions" into google and it comes up. I'd post a link but i'm not allowed do that for some reason.

    That site is brilliant :) you don't any other good ones? For theorems maybe? :)


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  • Registered Users Posts: 75 ✭✭jellytots95


    Can somebody help me please, what are the 3 theorems everyone is talking about ?
    Thanks in advance!

    I think they're the three ones at the end of geometry.. They're:

    If three parallel lines cut off equal segments on some transversal line, then they will cut off equal segments on any other transversal

    Let ABC be a triangle. If a line XY is parallel to Bc and cute AB in the ratio s:t, then it also cuts AC in the same ratio

    If two triangles are similar, then they're sides are proportional in order


  • Registered Users Posts: 5 Maths Help Needed


    I think they're the three ones at the end of geometry.. They're:

    If three parallel lines cut off equal segments on some transversal line, then they will cut off equal segments on any other transversal

    Let ABC be a triangle. If a line XY is parallel to Bc and cute AB in the ratio s:t, then it also cuts AC in the same ratio

    If two triangles are similar, then they're sides are proportional in order

    Thanks very much for the reply do you know what number theorems they are ?
    Thanks once again


  • Registered Users Posts: 75 ✭✭jellytots95


    Thanks very much for the reply do you know what number theorems they are ?
    Thanks once again

    11, 12 and 13 I think :)


  • Registered Users Posts: 5 Maths Help Needed


    11, 12 and 13 I think :)
    Yes I just looked there and thats the three you named. Is that all the theorems you need to know ?
    Thanks.


  • Registered Users Posts: 256 ✭✭Saskatchewan


    I wonder could we see a 75 mark coordinate geometry question.....


  • Registered Users Posts: 121 ✭✭miissjuly


    You're all going to PASS/get the grade you want. Don't worry. <3
    Focus on paper 2!


  • Closed Accounts Posts: 3,799 ✭✭✭onethreefive


    Maths is driving me crazy. Failed paper one i think and trying my hardest to bring it up to a pass. Can someone please tell me how to construct a perpendicular bisector of a triangle. I'm doing the circumcircle construction.


  • Registered Users Posts: 11,156 ✭✭✭✭HugsiePie


    Maths is driving me crazy. Failed paper one i think and trying my hardest to bring it up to a pass. Can someone please tell me how to construct a perpendicular bisector of a triangle. I'm doing the circumcircle construction.



    http://mathworld.wolfram.com/PerpendicularBisector.html


  • Registered Users Posts: 2,224 ✭✭✭robman60


    miissjuly wrote: »
    You're all going to PASS/get the grade you want. Don't worry. <3
    Focus on paper 2!

    Ok, but I'll be quoting this in August when I don't get an A1. :rolleyes:


  • Closed Accounts Posts: 3,799 ✭✭✭onethreefive


    I'm on the verge of throwing my maths book out the window. I've spent over half an hour trying to get the perpendicular bisector of a triangle :'(
    Thanks for the video it helped but I'm not sure what to do for the second line if that makes sense :(


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  • Registered Users Posts: 11,156 ✭✭✭✭HugsiePie


    I'm on the verge of throwing my maths book out the window. I've spent over half an hour trying to get the perpendicular bisector of a triangle :'(
    Thanks for the video it helped but I'm not sure what to do for the second line if that makes sense :(

    Theres a link under the video

    That might help


  • Closed Accounts Posts: 2,374 ✭✭✭Hotale.com


    I'm on the verge of throwing my maths book out the window. I've spent over half an hour trying to get the perpendicular bisector of a triangle :'(
    Thanks for the video it helped but I'm not sure what to do for the second line if that makes sense :(

    I don't think that question makes sense. "Bi" means two, a triangle has three sides... Unless they want you to split the area? I think to do that you need to split the altitude or something... I'm doing all my P2 study tomorrow.. :P


  • Registered Users Posts: 2,204 ✭✭✭Aspiring


    I'm so glad I did tech graph for the junior cert. Makes all this bisecting of lines and angles and all so much easier.


  • Registered Users Posts: 906 ✭✭✭Ompala


    Hotale.com wrote: »
    I don't think that question makes sense. "Bi" means two, a triangle has three sides... Unless they want you to split the area? I think to do that you need to split the altitude or something... I'm doing all my P2 study tomorrow.. :P

    Off the top of my head... perpendicular bisector refers to splitting one side of a triangle into two equal lengths


  • Closed Accounts Posts: 2,374 ✭✭✭Hotale.com


    Ompala wrote: »
    Off the top of my head... perpendicular bisector refers to splitting one side of a triangle into two equal lengths

    The question must be worded terribly so, it's "perpendicular" to only one side and you're not even bisecting the triangle if that's the case.


  • Registered Users Posts: 2,204 ✭✭✭Aspiring


    Yeah you're splitting the sides.
    Say you have triangle ABC
    Take your compass at A (put the metal part there). With the pencil part, draw an arc that is past halfway between A and B. Now put metal part at B, do the same thing but the other way around, but use the same radius arc. Draw a line between where the two arcs intersect. That's the perpendicular bisection of a line.

    Do this for another line (or two if you want). Where the two (three) intersect is your circumcentre.


  • Registered Users Posts: 297 ✭✭Daledge


    So I'm pretty confident for paper 2 having been one of the small few who's paper 1 went well, but what exactly should I make sure I know for Monday?


  • Registered Users Posts: 906 ✭✭✭Ompala


    Hotale.com wrote: »
    The question must be worded terribly so, it's "perpendicular" to only one side and you're not even bisecting the triangle if that's the case.

    I don't actually know what the question is,, just remember the terminology.
    Now you have me thinking, how do you bisect a triangle? Split it into two parts of equal areas? Surely there are infinite ways to do that...


  • Registered Users Posts: 960 ✭✭✭Conchir


    There's a website called studentxpress.ie that has the solutions for Paper One up on it. They're going up gradually, up to question 5 at the moment.

    Check at your own peril; I can only half remember my answers so it mightn't be great to look at :P


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  • Closed Accounts Posts: 2,374 ✭✭✭Hotale.com


    Ompala wrote: »
    I don't actually know what the question is,, just remember the terminology.
    Now you have me thinking, how do you bisect a triangle? Split it into two parts of equal areas? Surely there are infinite ways to do that...

    Onethreefive posted the question there a whole back I think.

    You can't bisect a triangle as far as I know...


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