Co Ordinate Geometry Qs

iCrazzy

I am struggling in thi question. Could someone please put me in the right direction
Q10 taken from18 of test and test 4.

skippy1977

In Q18 you can find the co-ordinates of the point where the line cuts the x-axis but letting y=0.
3x+4(0)=k
x=k/3

The co-ordinates of the point where the line cuts the y-axis but letting x=0.
3(0)+4y=k
y=k/4

This means the triangle has a base of k/3 units and a height of k/4 units.
Area of a Triangle is half the base x the height
Area of triangle is (1/24)k^2

skippy1977

In Q18 you can find the co-ordinates of the point where the line cuts the x-axis but letting y=0.
3x+4(0)=k
x=k/3

The co-ordinates of the point where the line cuts the y-axis but letting x=0.
3(0)+4y=k
y=k/4

This means the triangle has a base of k/3 units and a height of k/4 units.
Area of a Triangle is half the base x the height
Area of triangle is (1/24)k^2
Let this equal to 24 and solve.
k=24

skippy1977

Q10 can be done using the division of a line in a given ratio formula in the tables or simply just line them up and figure out how far each co-ordinate is translated.

(4,-3) to (2, -2) the x-co-ordinate goes down 2 units
(2,-2) to (-2,0) the x co-ordinate goes down a further 4 units)

This is a ratio of 1:2

If you check the y co-ordinates it translates down one unit then down another two.

confirms 1:2 ratio.