!! Maths HL paper 1 2016 - Before and After

TSMGUY

luftmensch wrote: »

That was easier than I anticipated.

Trouble now is, paper 2 is gonna be gruesome.

I suck at paper 2 anyway, so no love lost there. I just hope it isn't marked too harshly. lol at how much I stressed over financial maths!!!

By the way, was the acute angle 87 degrees?

pseudorachel

TSMGUY wrote: »

By the way, was the acute angle 87 degrees?

I got 58 degrees or something around that.

Appmaths97

TSMGUY wrote: »

I suck at paper 2 anyway, so no love lost there. I just hope it isn't marked too harshly. lol at how much I stressed over financial maths!!!

By the way, was the acute angle 87 degrees?

i got 52 degrees

DublinArnie

Appmaths97 wrote: »

i got 52 degrees

I got 28 degrees or something like that.

CreepyOnion

TSMGUY wrote: »

I suck at paper 2 anyway, so no love lost there. I just hope it isn't marked too harshly. lol at how much I stressed over financial maths!!!

By the way, was the acute angle 87 degrees?

I got 34

DublinArnie

How did you guys find the angle?

I TanQ = rate of change of slope (diff twice), then tan inverse to find the angle.

louisoc

Appmaths97 wrote: »

i got 52 degrees

Yeah me too, tan inverse of the slope?

That's the first I've heard of Pythagorean triples, bit annoying.

MashedPotato49

52 degrees

TSMGUY

DublinArnie wrote: »

I got 28 degrees or something like that.

Appmaths97 wrote: »

i got 52 degrees

pseudorachel wrote: »

I got 58 degrees or something around that.

LOL! That's that sorted then:D

I forgot to set my calculator to radians so I had to convert it myself.

randomlad727

I think I got around 34 degrees

louisoc

Anyone else get like (3.2, 1.6) for the point the pattern was approaching in the sequences question?

CreepyOnion

The integration question with the ball was the average value, right? So 1/b-a?

MomijiHime

I thought it was a weird paper..

DublinArnie

CreepyOnion wrote: »

The integration question with the ball was the average value, right? So 1/b-a?

Yeah

randomlad727

louisoc wrote: »

Anyone else get like (3.2, 1.6) for the point the pattern was approaching in the sequences question?

Yeah I got those values

TSMGUY

louisoc wrote: »

Anyone else get like (3.2, 1.6) for the point the pattern was approaching in the sequences question?

oh F***. I thought they meant it was converging to zero. I said zero for both and wrote a load of ****e about limits. Didn't know they wanted co-ordinates

DA7800

I thought it was a very nice paper! It went a lot better than it could have. It does have me worried for paper 2, though. Paper 2 is my weaker paper.

I got 29 degrees for my acute angle, inverse tan of the difference between the two slopes.

CreepyOnion

Who knows, maybe they've just permanently made the papers easier. One can dream

Appmaths97

DublinArnie wrote: »

How did you guys find the angle?

I TanQ = rate of change of slope (diff twice), then tan inverse to find the angle.

i got the fist derivative and found the slope for that point
i got -1.3 slope is rise over run the rise was -1.3 and the run was 1 and i tan inversed that

Soolander

F*** i just realised my calculator was in radian mode when i was trying to calculate the angle. No wonder i couldnt get it. F******* stupid mistake.

TSMGUY

Appmaths97 wrote: »

i got the fist derivative and found the slope for that point
i got -1.3 slope is rise over run the rise was -1.3 and the run was 1 and i tan inversed that

teach me how do the "fist" derivative, I never learned that:)

Giotar

Probably the easiest HL Maths exam I've ever done.

Giotar

louisoc wrote: »

Anyone else get like (3.2, 1.6) for the point the pattern was approaching in the sequences question?

Yep sounds familiar.

louisoc

For finding the parabola of g(x), what did I have to do? I dicked around with the translation figures I got and ended up with some sort of a curve equation, but I didn't get time to see whether it worked.

daraghwal

So to get the angle was it. 1. get the slope at the point of the hoop by differentiating the equation and subing in the values, 2. Find theta (howevery you spell that) by using the Tan theta formula to find angle between two lines. I found the slope of the line to be -1.2 something and the other 0, then got tan inverse of that and came out with something like 52?

legocrazy505

Better than my mock but just realised now I didn't fully finish the inverse function. Should get most of the marks. Didn't get some things, probably high C at least but it really depends on the marking schemes.

Happy there wasn't any overly difficult geometric series or arithmetic in it. Would have liked some financial but the paper overall wasn't bad so I won't complain about it being left out.

Giotar

legocrazy505 wrote: »

Better than my mock but just realised now I didn't fully finish the inverse function. Should get most of the marks. Didn't get some things, probably high C at least but it really depends on the marking schemes.

That's the one thing I screwed up on and I'm kicking myself because I felt as if my exam was borderline B3/C1. For some reason my brain told me that -1 meant derive it, not find the inverse

Soolander

So now that Paper 1 is finished anyone have any notions about Paper 2? I think external circles might come up.

smartz

Can someone post the paper?

LFC CONNAUGHTON

Realise now I messed up that slope question and didn't do the inverse function right either, there goes my hope at an A more than likely

Soolander

Was the inverse function not f(x) = y , x on its own , replace y with x ?

Corkalex

I have a feeling that they'll throw a financial maths question into paper two

emersyn

That has to have been one of the nicest maths papers ever written!! Really happy, let's hope paper 2 isn't awful now

legocrazy505

Soolander wrote: »

Was the inverse function not f(x) = y , x on its own , replace y with x ?

Yeah pretty much.

Let f(x)=y
Switch the x and y
Solve for y
Replace y with f^-1(x)

I forgot to fully solve it basically.

daraghwal

smartz wrote: »

Can someone post the paper?

I would be hoping people handed up their papers

luftmensch

smartz wrote: »

Can someone post the paper?

It should be up on examinations.ie at around 6:00pm.

Corkalex wrote: »

I have a feeling that they'll throw a financial maths question into paper two

I really doubt it. Financial maths is paper 1 material.

Oisin1001

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

MomijiHime

daraghwal wrote: »

I would be hoping people handed up their papers

People who do it through Irish get to keep the English paper.

hubluh

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

I think you get the perfect square of the first equation and replace the max point in f (x) for the max of g (x)?

DublinArnie

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

I used the complete square method by using the turning point to form an equation, but I'm not sure if that's correct.

(x-h)^2 + K

pseudorachel

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

thisis what i did anyway

let g(x)=aX^2 + bx + c

c is 2 because y=2 when x=0

sub in the point that was given to get one equation

g'(x)=2ax+c and sub in the max height

now you have simultaneous equations and solve. theres probably an easier way but that's what I did.

Leavingcert16

Did anyone find the paper hard

CathalRyano

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

Yep, so you sub in (x-0.5) as the x value in the formula, and you sub in (y+0.565) as the y in the formula. Gets you something like -0.273(x-0.5)x^2 + something(x-0.5) + something = y+0.565. And then you just simplify that.

randomlad727

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

I used the point of its maximum height and put it into the formula for when you complete the square (x-b)^2+c

Oisin1001

DublinArnie wrote: »

I used the complete square method by using the turning point to form an equation, but I'm not sure if that's correct.

(x-h)^2 + K

Ah, I had the right idea anyway. Cheers

Didn't expect ten people to reply!

Appmaths97

Oisin1001 wrote: »

Anybody know how to get the last part of Q8(b) where you have to get the formula for g(x), which is the path of the second basketball thrown? Think that was one of the two parts I didn't get worked out completely in the end.

i think you where supposed to replace y in the f(x) to y + translation of y coordinate, and replace x in the f(x) with x + translation of x coordinate.

You could also doing it by subbing in a few coordinates into ax squared + bx +c and solve for a,b and c

louisoc

If you start attempting something the right way, cross it out and do it the wrong way, does that negate any potential effort marks?

daraghwal

The papers are up on examinations.ie now

Wolframalpha is good for checking answers

Appmaths97

how did you all do 1c? I did long-division and it got very messy

DublinArnie

Appmaths97 wrote: »

how did you all do 1c? I did long-division and it got very messy

Long divison worked for me.

For the basketball angles question, it said to the horizontal.

You guys who got answers in the 50s got it right.

I got the entry angle, not the angle to the horizontal.