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Phase 6 electrical past papers and model answers

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  • 18-01-2017 10:33pm
    #1
    phil21_06
    Registered Users Posts: 20 ✭


    Hi. Currently in phase 6 electrical. Hoping someone might have any past papers craft or science with model answers . Any help is much appreciated. Thanks in advance
    Reply


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    #2
    2011
    Moderators, Home & Garden Moderators, Technology & Internet Moderators, Regional East Moderators Posts: 12,595 Mod ✭✭✭✭2011


    If you post questions here that you are having difficulty with I'm sure that someone will assist.


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    #3
    Dalysinbed
    Registered Users Posts: 1 ✭Dalysinbed


    I have a few were are you based


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    #4
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    Dalysinbed wrote: »
    I have a few were are you based

    Hi im in lucan


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    #5
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    Would anyone be able to help with this question by any chance. Thanks in advance


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    #6
    2011
    Moderators, Home & Garden Moderators, Technology & Internet Moderators, Regional East Moderators Posts: 12,595 Mod ✭✭✭✭2011


    Output voltage / input voltage = - R2 / R1 = Gain


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    #7
    micks
    Registered Users Posts: 840 ✭✭✭micks


    sent you a link to some


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    #8
    dolittle
    Registered Users Posts: 706 ✭✭✭dolittle


    phil21_06 wrote: »
    Would anyone be able to help with this question by any chance. Thanks in advance

    its an inverting amplifier

    Av = R2/R1 =-V out /V in

    R1 = R2 ( -V in / V out)

    1000 (100/2200)

    45.45 ohms


    I Think


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    #9
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    dolittle wrote: »
    its an inverting amplifier

    Av = R2/R1 =-V out /V in

    R1 = R2 ( -V in / V out)

    1000 (100/2200)

    45.45 ohm

    I Think

    Cheers. Looks good. How did u transpose that formula. Its wreaking my head ha


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    #10
    aido79
    Registered Users Posts: 5,374 ✭✭✭aido79


    phil21_06 wrote: »
    Cheers. Looks good. How did u transpose that formula. Its wreaking my head ha

    Just like every other formula try not to over think it too much. If you do something to one side of the formula do the same to the other:

    Av = R2/R1 =-V out /V in

    First you flip both sides so you get:

    R1/R2 = -V in/V out

    Then to isolate R1 you multiply each side by R2 and get:

    R1 = R2 ( -V in / V out)

    1000 (100/2200)

    45.45 ohms


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    #11
    Copper_pipe
    Registered Users Posts: 11,553 ✭✭✭✭Copper_pipe


    Have a textbook in PDF format if you want it.

    Electronic Devices
    , should help you out


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    #12
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    Copper_pipe wrote: »
    Have a textbook in PDF format if you want it.

    Electronic Devices
    , should help you out

    Thanks. Ye if u think it will help. Cheers. My email <snip> thanks


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    #13
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    aido79 wrote: »
    Just like every other formula try not to over think it too much. If you do something to one side of the formula do the same to the other:

    Av = R2/R1 =-V out /V in

    First you flip both sides so you get:

    R1/R2 = -V in/V out

    Then to isolate R1 you multiply each side by R2 and get:

    R1 = R2 ( -V in / V out)

    1000 (100/2200)

    45.45 ohms

    Thanks. Will give it go


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    #14
    Zaph
    Registered Users, Subscribers Posts: 47,317 ✭✭✭✭Zaph


    phil21_06, I've removed your e-mail address from the post above. It's never a good idea to post your e-mail address on a public forum like Boards as unfortunately some people are dicks and may use it inappropriately. You can sort out contact details with the other poster via PM.


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    #15
    Stoner
    Registered Users Posts: 10,952 ✭✭✭✭Stoner


    Also guys while we are here, can you have a look the age of some of the threads you are responding to, I've had to delete a few as a user helped a fellow user out years ago but continues to get hit with requests for papers and help requests via PM

    So please post your question and accept help as it appears, but don't just spam other users with help requests from old posts please, there is some decent help here and we don't want to kill the thread.


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    #16
    phil21_06
    Registered Users Posts: 20 ✭phil21_06


    Zaph wrote: »
    phil21_06, I've removed your e-mail address from the post above. It's never a good idea to post your e-mail address on a public forum like Boards as unfortunately some people are dicks and may use it inappropriately. You can sort out contact details with the other poster via PM.

    Never thought. Thanks


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