Python - getting info from a url from with returned results

maccored

Hi - Im teaching myself some python and I'm stuck.

I can pull info back from an API, but within that info is another set of urls, from which I need further data. If I use this:

import requests
url = "https://pokeapi.co/api/v2/pokemon-color/"
data = requests.get(url)
parsed_data = data.json()
pokemon_types = parsed_data['results']
for p_type in pokemon_types:
    url = ['results']['url']

.. it'll print the resulting colour name and url which then has further data. I cant figure out how to pull more data from the urls and print that, rather than the url itself. i know how to separate the data that I need to get from the urls, but I dont know how to open those urls, so i can search and then print what I need. Anyone have an pointers or anything online to help me figure it out?

srsly78

https://pypi.org/project/beautifulsoup4/

maccored

srsly78 wrote: »

https://pypi.org/project/beautifulsoup4/

Im using JSON and pulling the data from an API .... would I still use beautifulsoup?

srsly78

It can parse everything.

28064212

srsly78 wrote: »

https://pypi.org/project/beautifulsoup4/

Why would you recommend a HTML/XML scraping library for a JSON API endpoint?

OP, you've already done what you're looking for help on. You have a URL, you need to contact it (with requests), load it into a JSON object, and select the nodes you want. The 4 lines of code inside your for loop should be almost the same as the 4 lines preceding it. The main change would be that you're assigning a value from p_types to url, instead of a hard-coded string

maccored

28064212 wrote: »

Why would you recommend a HTML/XML scraping library for a JSON API endpoint?

OP, you've already done what you're looking for help on. You have a URL, you need to contact it (with requests), load it into a JSON object, and select the nodes you want. The 4 lines of code inside your for loop should be almost the same as the 4 lines preceding it. The main change would be that you're assigning a value from p_types to url, instead of a hard-coded string

thanks - I have that sorted now. I may make another thread with my next issue ...