Bash: Getting variable directory name for directory which contains spaces and a single quote

veryangryman

Here is an example directory

drwxr-xr-x 1 vangryman 197121 0 Jul 29 13:27 "2022-07-29 13.26.09 Very Angryman's Personal Meeting Room"/

So i'm trying to get the directory name to later cd into it

$ cat get_zoom.sh

#!/bin/bash

dir=$(ls -tr ../../Downloads/Documents/Zoom/ | tail -1)

cd "\"\"$dir\"\""

pwd

But no joy with how i wrap quotes

$ sh -x get_zoom.sh

++ ls -tr ../../Downloads/Documents/Zoom/

++ tail -1

+ dir='2022-07-29 13.28.21 Very Angryman''\''s Personal Meeting Room'

+ cd '""2022-07-29 13.28.21 Very Angryman'\''s Personal Meeting Room""'

get_zoom.sh: line 3: cd: ""2022-07-29 13.28.21 Very Angryman's Personal Meeting Room"": No such file or directory

Igotadose

Does cd "${dir}" work any better? I think your \"\" wrapper is what's messing it up.

Skrynesaver

 cd "$(/bin/ls -tr  ../../Downloads/Documents/Zoom/ | tail -1)"

Works here

veryangryman

Thanks guys got sorted

zoom_path="/c/Users/$(whoami)/Downloads/Documents/Zoom/"

cd "${zoom_path}""$(ls -tr ${zoom_path} | tail -1)"