Fool

Void

#include <stdio.h>
#define p(x) \
printf("%c", \
f(x++)));}
#define f(x) arr[x]
#define s(x) int \
main(x){
#define R(y,z) (y>>z)
#define L(w,x) \
(w<<x)\

s(void) int i,arr[14]={ 'M',
'r',
'.',
' ',
'T',
' ',
'S',
'a',
'y',
's',
';'};f(4)=f(8)=f(3);f(13)=R((f(0)=(R(f(2),1))+(R(f(1),1)
)),3);f(2)=f(5)=f(1)+2;f(1+(L(1,1)))=((L(1,7))-7);f(10)=f(10+R((0xA&0xB),3))
=(f(2)-(1+(L(1,2))));f(7)=((f(9)=(f(6)=(f(1)=0x069)-1)-2)-1);f((L(2,2)+(L(1,2)
)))=(0xFD&0x16E);for(i=0;i<14;p

Shiminay

I think you should have put UBB "code" tags around that...

#include <stdio.h>
#define p(x) \
printf("%c", \
f(x++)));}
#define f(x) arr[x]
#define s(x) int \
main(x){
#define R(y,z) (y>>z)
#define L(w,x) \
(w<<x)\

s(void) int i,arr[14]={ 'M',
'r',
'.',
' ',
'T',
' ',
'S',
'a',
'y',
's',
';'};
f(4)=f(8)=f(3);f(13)=R((f(0)=(R(f(2),1))+(R(f(1),1)
)),3);
f(2)=f(5)=f(1)+2;f(1+(L(1,1)))=((L(1,7))-7);
f(10)=f(10+R((0xA&0xB),3))=(f(2)-(1+(L(1,2))));
f(7)=((f(9)=(f(6)=(f(1)=0x069)-1)-2)-1);
f((L(2,2)+(L(1,2))))=(0xFD&0x16E);

for(i=0; i<14 ;p

Like so

---

All the best,

Dav
@B^)
My page of stuff

[This message has been edited by Kharn (edited 28-07-2000).]

MiCr0

someone put up the output

ecksor

Originally posted by MiCr0:
someone put up the output

I would, but it didn't compile for me.

Trojan

I would, but it didn't compile for me.

Same as that. FYI:

Compiling D:\TC\PCANTEST.C:
Error D:\TC\PCANTEST.C 25: Undefined symbol 'p' in function main
Error D:\TC\PCANTEST.C 25: For statement missing ) in function main
Error D:\TC\PCANTEST.C 26: Compound statement missing } in function main
Warning D:\TC\PCANTEST.C 26: Function should return a value in function main

Al.

--

amdsoft.com

Jay

Lads, I think he's taking the **** with that 'code'.

What is it 'supposed' to do anyway?

ecksor

Originally posted by Jay:
Lads, I think he's taking the **** with that 'code'.

What is it 'supposed' to do anyway?

Ok, I took a go at it (I am a closet C ninja ) and figured out that there are only a couple of characters missing off the end.
So, here it is ...

#include <stdio.h>
#define p(x) \
printf("%c", \
f(x++)));}
#define f(x) arr[x]
#define s(x) int \
main(x){
#define R(y,z) (y>>z)
#define L(w,x) \
(w<<x)\

s(void) int i,arr[14]={ 'M',
'r',
'.',
' ',
'T',
' ',
'S',
'a',
'y',
's',
';'};f(4)=f(8)=f(3);f(13)=R((f(0)=(R(f(2),1))+(R(f(1),1)
)),3);f(2)=f(5)=f(1)+2;f(1+(L(1,1)))=((L(1,7))-7);f(10)=f(10+R((0xA&0xB),3))
=(f(2)-(1+(L(1,2))));f(7)=((f(9)=(f(6)=(f(1)=0x069)-1)-2)-1);f((L(2,2)+(L(1,2)
)))=(0xFD&0x16E);for(i=0;i<14;p(i)

Trojan

Lads, I think he's taking the **** with that 'code'.
What is it 'supposed' to do anyway?

Nah, the whole point is that the code is supposed to be obfuscated, check out IOCCC (if it's up, seem s to be down atm). The idea is to try and figure what it does before you run it... good luck, but I don't have that much time on my hands...

Al.

Kali

pah obfuscated c ..
perl is the king of it

Jay

blup

[This message has been edited by Jay (edited 02-08-2000).]

Jay

Correct code

#include <stdio.h>

#define p(x) printf("%c", f(x++)));}

#define f(x) arr[x]

#define s(x) int main(x){

#define R(y,z) (y>>z)

#define L(w,x) (w<<x) 

s(void) int i,arr[14]={ 'M','r','.',' ','T',' ','S','a','y','s',';'};

f(4)=f(8)=f(3);
f(13)=R((f(0)=(R(f(2),1))+(R(f(1),1))),3);

f(2)=f(5)=f(1)+2;
f(1+(L(1,1)))=((L(1,7))-7);

f(10)=f(10+R((0xA&0xB),3))=(f(2)-(1+(L(1,2))));

f(7)=((f(9)=(f(6)=(f(1)=0x069)-1)-2)-1);

f((L(2,2)+(L(1,2))))=(0xFD&0x16E);

for(i=0; i<14 ;p(i)

Output:

Pity the fool

Jay

Balls, sure I didnt even notice X_OR's post, he has the correct code there already.

X_OR - you L33T Ninja C programmer.