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PHP and Imagemagick

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  • 26-04-2005 12:15pm
    #1
    marcphisto
    Registered Users Posts: 180 ✭✭


    Hi,

    I am getting an error using imagemagick and I cannot figure out where it is going wrong.

    What I am basically doing is uploading an image file from a form and creating a thumbnail and popup image from it. This method has served me well in the past, I have used identical code on previous sites.

    here is my code segment.

    [PHP]

    $current_size = getimagesize("../img/$perm");
    $current_img_width = $current_size[0];
    $current_img_height = $current_size[1];

    $new_img_width = 300;
    $new_img_height = round((($new_img_width / $current_img_width) * $current_img_height));

    $imObj = new ImageMagick($HTTP_POST_FILES);
    $imObj -> setVerbose(FALSE);
    $imObj -> setTargetdir($imgdir);
    $imObj -> Resize($new_img_width,$new_img_height, "fit");
    $imObj -> Convert("jpg");
    $perm = $imObj -> Save('main_');

    $thumbheight = round ( ($new_img_height / 3) );

    $imObj -> Resize(100,$thumbheight, "fit");
    $imObj -> Convert("jpg");
    $thumb = $imObj -> Save('thumb_');
    $imObj -> CleanUp();

    [/PHP]

    $imgdir is declared as an absolute path to the directory for the images

    the error I am getting is ImageMagick: Corrupt image

    I have checked the image copied up by php and it is fine.

    Anyone have any ideas?


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