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Math..............

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  • 03-05-2005 7:38pm
    #1
    Closed Accounts Posts: 28


    Any1 got any decent maths notes or knoe where to get any.....
    And any1 want to enlighten me on this q -
    Differentiation- if x = a.coswt + b.sin.w.t, where a,w,t,b are constants..
    show that
    d2x + w2x = 0
    dt2

    2's supposed to be squared btw..............???????????

    and trig........ just not my cup of tea..........


Comments

  • Registered Users Posts: 68,317 ✭✭✭✭seamus


    Well, where you need to start, is look at what you have, and what you need.

    you have an x, and you need a d^2x. You first clue is: differentiate.


  • Closed Accounts Posts: 28 poppins9000


    ok obviously nuf i gathered that 1!!................ :eek:
    it just dont seem to work out right............
    can you do it so...............? :confused:


  • Registered Users Posts: 1,496 ✭✭✭*Angel*


    Differentiation- if x = a.coswt + b.sin.w.t, where a,w,t,b are constants..
    show that
    d2x + w2x = 0
    dt2

    surely if it's d2x/dt2 then the 't' cannot be a constant? Check that you wrote it down right...


  • Registered Users Posts: 1,496 ✭✭✭*Angel*


    Okay so here you go,

    x = acos(wt) + bsin(wt)

    dx/dt = -awsin(wt) + bwcos(wt)

    d2x/dt2 = -aw2cos(wt) - bw2cos(wt)

    d2x/dt2 = -w2(acoswt + bsinwt) = -w2x


  • Registered Users Posts: 33,518 ✭✭✭✭dudara


    *angel* is right. What you're actually doing here is showing that the expression y = aSin(wt) + bCos(wt) satisifies the differential eq you were given.

    First off, rewrite it

    d2y/dt2 = -w^2y

    so you're being asked to show that the 2nd derivative of the expression you were given equals the original expression times w^2

    y = aSin(wt) + bCos(wt)

    dy/dt = waCos(wt) - bwSin(wt)

    d2y/dt2 = -w^2aSin(wt) -w^2bCos(wt)
    = -w^2(aSin(wt) + bCos(wt))
    = -w^2(y)


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  • Closed Accounts Posts: 28 poppins9000


    Yeah.......i did right it down wrong,just rang my mate.....that would've been smart of me!
    reckon i was just making a stupid mistake..... leaving out the minus sign when dif it..........AH how annoying..
    Anyhoo cheers guys.............


  • Registered Users Posts: 6,423 ✭✭✭tinkerbell


    If you want a decent maths book, don't bother with those revision books.

    Get Text & Tests 4 & 5 - they are fantastic. I worked through those two books for my Leaving revision (we used a different book at school) and they are so much better than any other maths book I used while in school. Then again, that was four years ago - unless the course has changed since then?


  • Registered Users Posts: 2,945 ✭✭✭D-Generate


    As the applied maths students should be able to see, thats S.H.M and the amplitude is sqrt(a^2 + b^2) :)


  • Closed Accounts Posts: 225 ✭✭Rredwell


    tinkerbell wrote:
    Get Text & Tests 4 & 5 - they are fantastic. I worked through those two books for my Leaving revision (we used a different book at school) and they are so much better than any other maths book I used while in school. Then again, that was four years ago - unless the course has changed since then?

    Well, there are new TT4 and TT5 now - the chapters are swapped around a bit - and they are great, I agree.

    What book did you have, Tinkerbell? Discovering Maths?


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  • Registered Users Posts: 2,945 ✭✭✭D-Generate


    Must say I like Discovering Maths, questions are tougher than the actual papers so its good practice.


  • Registered Users Posts: 33,518 ✭✭✭✭dudara


    I'm giving LC Honours Maths grinds at the moment to a guy using TT4 and TT5. To be honest, I prefer discovering Maths. I think it's a higher standard of book.


  • Registered Users Posts: 1,496 ✭✭✭*Angel*


    I personally like the Text and Tests 4 & 5 (new versions) but I haven't used any others so... I don't like revision books for maths though.

    poisonapplet is an ok site for the leaving cert.

    *EDIT* Is anyone here doing the further geometry option question in paper I, cos I can't find stuff for it anywhere, not even in books?


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