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Proof in the magical bag of maths tricks

Beno · 2005-06-12 19:37:09

havin a problem Anyone have this book please help me on page 401 paper 2 how does he get from a^2 + B^2 / Sqr Root of a^2 + B^2 = Sqr Root of a^2 + B^2 thx

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12-06-2005 8:37pm

#1

Beno

Registered Users Posts: 215 ✭✭

Join Date: July 2004

Posts: 171

havin a problem
Anyone have this book please help me
on page 401 paper 2

how does he get from a^2 + B^2 / Sqr Root of a^2 + B^2 = Sqr Root of a^2 + B^2

thx

0

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#2 12-06-2005 9:34pm
Beno

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Join Date: July 2004

Posts: 171

no need figured it out anyway since a^2 + b^2 = C^2

this means that a^2 + B^2 / Sqr Root of a^2 + B^2 =
C^2/Sqr Root of C^2 =
C =
Sqr Root of C^2 =
Sqr Root of a^2 + B^2

I am not a thick as i thought :rolleyes:

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#3 12-06-2005 10:44pm
oq4v3ht0u76kf2

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Posts: 1850

x / root(x) = root(x)

Always.

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