Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie

Partial Maths II (H) Solutions

Options
  • 13-06-2005 7:34pm
    #1
    oq4v3ht0u76kf2
    Closed Accounts Posts: 2,028 ✭✭✭


    In the attached PDF file... had planned on doing the whole paper but only ended up doing most of questions 1 to 3... got bored. I'll have a complete set done on Wednesday.

    Oh, and I probably got less in maths than most of you so if/when you see any errors please point them out so I can fix them. And if anyone wants to contribute further solutions that'd be handy.

    G'luck,
    Bob

    Edit: updated file, fixed a silly divide-by-0 error. Blame tiredness! Not me! :p


Comments

  • Options
    #2
    sixdraw
    Closed Accounts Posts: 91 ✭✭sixdraw


    do i see you dividing by zero to get zero in your solutions? One of the biggest things you never do is divide by zero.its infinity anyways not zero.
    Allthough you are right in saying the line is parallel to the y-axis as the slope of this line is infinity. a line of slope 0 is parralel to the x-axis


  • Options
    #3
    oq4v3ht0u76kf2
    Closed Accounts Posts: 2,028 ✭✭✭oq4v3ht0u76kf2


    Possibly... I'm quite tired today although still, blasphemy! I've modified the file, thanks for pointing it out!


  • Options
    #4
    D-Generate
    Registered Users Posts: 2,945 ✭✭✭D-Generate


    3 (a) also asked for the equation of the line passing through p perpindicular to L2, not just fo teh point p. Only spotted that at the very end but in my rush i messed up the slope (d'oh!)


  • Options
    #5
    Rnger
    Closed Accounts Posts: 1,266 ✭✭✭Rnger


    Vectors Q 2 (a) isnt right i think. You were asked where the point was methinks not to rearranged it in terms of a and b.

    If you draw the parrelellelelgram and follow the steps of 1/2a then 1/2b then -c you find d is below the gram. I dont have paint on this pc to illustrate :(


  • Options
    #6
    Alkers
    Registered Users Posts: 6,837 ✭✭✭Alkers


    Rnger wrote:
    parrelellelelgram
    :D:D:D


  • Advertisement
  • Options
    #7
    Breezer
    Registered Users Posts: 3,228 ✭✭✭Breezer


    Got this for parallelogram thing, I think it's what Rnger means


  • Options
    #8
    randomfella
    Closed Accounts Posts: 728 ✭✭✭randomfella


    maybe its what he means. Def not what i got. i got it in the same height except it is to the left in the centre. Maybe i'm wrong...


  • Options
    #9
    Breezer
    Registered Users Posts: 3,228 ✭✭✭Breezer


    A good few people seemed to get that but then after much discussion they thought I was probably right. I really don't know to be honest - it's 1.66% of the exam and you'll get an attempt mark anyway so I wouldn't worry over it


  • Options
    #10
    snappieT
    Registered Users Posts: 3,357 ✭✭✭snappieT


    That image for the vector is correct btw.

    I drew in each of the vectors also to illustrate how I got my answer.
    vectors.gif


Advertisement